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Flow Measurement P,- Ps - Nh В :Ah P, – Pg = y Ah (1) AP = Hence, Ah A 2g Since, V = A where Q is the flow rate in [m/s] or [ft/s], and A is the flow area of the section in [m²] or [fi²] V; -v 1 Q² _Q² 2g 2g[ A A Q²| 1 Substituting, Ah | 2g[ A A 1 K = 1 1 Let K be a geometry constant of the venture tube, (2) 2g AB A Ah = KQ² Substituting for A, Az and g in both unit systems, we get; Thus (3) K = 4952170 s² / m°| for Q in [m³/s] K = 12950 s² / ft°| for Q in [ft/s] Ah Solving for (4 a) Venturi K Taking into account the discharge coefficient C, the obtained flow rate is Ah --(4b) Venturi K

Flow Measurement P,- Ps - Nh В :Ah P, – Pg = y Ah (1) AP = Hence, Ah A 2g Since, V = A where Q is the flow rate in [m/s] or [ft/s], and A is the flow area of the section in [m²] or [fi²] V; -v 1 Q² _Q² 2g 2g[ A A Q²| 1 Substituting, Ah | 2g[ A A 1 K = 1 1 Let K be a geometry constant of the venture tube, (2) 2g AB A Ah = KQ² Substituting for A, Az and g in both unit systems, we get; Thus (3) K = 4952170 s² / m°| for Q in [m³/s] K = 12950 s² / ft°| for Q in [ft/s] Ah Solving for (4 a) Venturi K Taking into account the discharge coefficient C, the obtained flow rate is Ah --(4b) Venturi K

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
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Fluid mechanics 

1. Convert the units that are blank with the given data
2. Use equations to obtain results from the given information.

Flow Measurement P- PB Ah AP = P - P =y Ah A (1) 2 v? В A Ah = 2g Hence, V = Q A Since, where Q is the flow rate in [m³%s] or [ft/s], and A is the flow area of the section in [m²] or [ft²] V; -V; 1 [Q Q°] В A 2g 2g[ 4 A 1 1 Substituting, Ah 2g [ A A 1 K 2g[ 4 A 1 1 Let K be a geometry constant of the venture tube, (2) KOʻ-- Ah = KQ² Substituting for A, Az and g in both unit systems, we get; Thus (3) B K = 4952170 s² /m°| for Q in [m³/s] K = 12950 s' / ft° for Q in [ft/s] Ah Solving for Qventuri V K -(4 a) Taking into account the discharge coefficient C, the obtained flow rate is Ah Qventuri = C, V K -(4b)
Transcribed Image Text:Flow Measurement P- PB Ah AP = P - P =y Ah A (1) 2 v? В A Ah = 2g Hence, V = Q A Since, where Q is the flow rate in [m³%s] or [ft/s], and A is the flow area of the section in [m²] or [ft²] V; -V; 1 [Q Q°] В A 2g 2g[ 4 A 1 1 Substituting, Ah 2g [ A A 1 K 2g[ 4 A 1 1 Let K be a geometry constant of the venture tube, (2) KOʻ-- Ah = KQ² Substituting for A, Az and g in both unit systems, we get; Thus (3) B K = 4952170 s² /m°| for Q in [m³/s] K = 12950 s' / ft° for Q in [ft/s] Ah Solving for Qventuri V K -(4 a) Taking into account the discharge coefficient C, the obtained flow rate is Ah Qventuri = C, V K -(4b)
Processing Results Water's Temperature: 2 K = 4952170 s²/m °C Water's Specific Weight, y = kN/m3 Measured Flow Rate Measured Ah, Flow Rate from Venturi , Coefficient C From Rotameter from manometer eq. (4а) Qrotameter Trial C = LPM m³/s [in] [m] m³/s LPM Venturi 1 1.3 7-5 Water's Temperature: 69.8 °F K = 12950 s²/ ft Water's Specific Weight, y = 62.30 lb/ft³ Measured Flow Rate Measured Ah, Flow Rate from Venturi , Coefficient C From Rotameter from manometer eq. (4a) Qrotameter C = Trial Qventuri GPM ft/s [in] [ft] ft/s GPM 1 1.9 2.5 2 2.5 3 3.
Transcribed Image Text:Processing Results Water's Temperature: 2 K = 4952170 s²/m °C Water's Specific Weight, y = kN/m3 Measured Flow Rate Measured Ah, Flow Rate from Venturi , Coefficient C From Rotameter from manometer eq. (4а) Qrotameter Trial C = LPM m³/s [in] [m] m³/s LPM Venturi 1 1.3 7-5 Water's Temperature: 69.8 °F K = 12950 s²/ ft Water's Specific Weight, y = 62.30 lb/ft³ Measured Flow Rate Measured Ah, Flow Rate from Venturi , Coefficient C From Rotameter from manometer eq. (4a) Qrotameter C = Trial Qventuri GPM ft/s [in] [ft] ft/s GPM 1 1.9 2.5 2 2.5 3 3.
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