None Q6/ Using the characteristics shown in figures below1) Determine Bac at IB = 70 uA and VCE = 10 V2) Determine Bdc at IB= 50 uA and VCE = 10V3) Using the Bdc determined in (2) find ICBO4) find the value of Ic if VBE =0.75 V and VCE = 12.5Vtlc (mA)90 μΑ80 uA1B (HA)70 HA60 μΑVCE = 1 VVCE = 10 V10090VCE = 20 V(Saturation region) 550 HA8040 HA7030 µA60(Active region)5020 μΑ40302.10 μΑ20=0HA1020 VCE (V)1015(Cutoff region)ICEO BI CBo0.20.40.6 0.81.0VBE (V)(a)(b)3.

flc (mA) 90 HA 80 uA B (HA) VCE = 1 V VCE = 10 V 70 μΑ 100 60 HA VCE = 20 V 90 80 (Saturation region) 5 50 HA 40 µA 70 30 HA 60 (Active region) 20 μΑ 50 40 10 HA 30 20 -0 HA 10 15 20 VCE (V) 10 (Cutoff region) ICEO = BIcBo 0.2 0.4 0.6 0.8 1.0 VBE (V)

flc (mA) 90 HA 80 uA B (HA) VCE = 1 V VCE = 10 V 70 μΑ 100 60 HA VCE = 20 V 90 80 (Saturation region) 5 50 HA 40 µA 70 30 HA 60 (Active region) 20 μΑ 50 40 10 HA 30 20 -0 HA 10 15 20 VCE (V) 10 (Cutoff region) ICEO = BIcBo 0.2 0.4 0.6 0.8 1.0 VBE (V)

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Concept explainers

KVL and KCL

KVL stands for Kirchhoff voltage law. KVL states that the total voltage drops around the loop in any closed electric circuit is equal to the sum of total voltage drop in the same closed loop.

Sign Convention

Science and technology incorporate some ideas and techniques of their own to understand a system skilfully and easily. These techniques are called conventions. For example: Sign conventions of mirrors are used to understand the phenomenon of reflection and refraction in an easier way.

Question

None

Q6/ Using the characteristics shown in figures below
1) Determine Bac at IB = 70 uA and VCE = 10 V
2) Determine Bdc at IB= 50 uA and VCE = 10V
3) Using the Bdc determined in (2) find ICBO
4) find the value of Ic if VBE =0.75 V and VCE = 12.5V
tlc (mA)
90 μΑ
80 uA
1B (HA)
70 HA
60 μΑ
VCE = 1 V
VCE = 10 V
100
90
VCE = 20 V
(Saturation region) 5
50 HA
80
40 HA
70
30 µA
60
(Active region)
50
20 μΑ
40
30
2.
10 μΑ
20
=0HA
10
20 VCE (V)
10
15
(Cutoff region)
ICEO BI CBo
0.2
0.4
0.6 0.8
1.0
VBE (V)
(a)
(b)
3.

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