fl-8)== y= 3/x at point (-8;2) %3D m =

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Find f(-8) and m and b
Certainly! Below is the transcription of the image:

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**Mathematics Exploration: Understanding Cube Roots**

If \( f(x) = \sqrt[3]{x} \)

Calculate \( f(-8) = \) [blank box for answer]

The function is \( y = \sqrt[3]{x} \) at the point \((-8, 2)\).

Calculate the slope \( m = \) [blank box for answer]

--- 

This activity requires evaluating the function \( f(x) = \sqrt[3]{x} \) specifically at \( x = -8 \) to find \( f(-8) \). The function's behavior is also considered at the point \((-8, 2)\), and the task is to determine the slope \( m \) at this location.
Transcribed Image Text:Certainly! Below is the transcription of the image: --- **Mathematics Exploration: Understanding Cube Roots** If \( f(x) = \sqrt[3]{x} \) Calculate \( f(-8) = \) [blank box for answer] The function is \( y = \sqrt[3]{x} \) at the point \((-8, 2)\). Calculate the slope \( m = \) [blank box for answer] --- This activity requires evaluating the function \( f(x) = \sqrt[3]{x} \) specifically at \( x = -8 \) to find \( f(-8) \). The function's behavior is also considered at the point \((-8, 2)\), and the task is to determine the slope \( m \) at this location.
Expert Solution
Step 1

We are given the function f(x)=x3.

Here, 

             f(-8)=-83=-2.

Now, we need to find Slopeoffx=x3,at-8,-2.

So, f'(x)=13x23 .

When x=-8,

               13(-8)23=112-123=112

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