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- A new car dealer is leasing various brand new randomly selected models for the monthly rates listed below. Estimate the true population variance in leasing rates with 90% confidence. Assume the variable is normally distributed. Round to the nearest hundredth for all calculations. 170 172 198 240 241 248A scientist claims that pneumonia causes weight loss in mice. The table shows the weights (in grams) of six mice before infection and two days after infection. At a=0.05, is there enough evidence to support the scientist's claim? Assume the samples are random and dependent, and the population is normally distributed. Mouse 1 4 6. Weight (before) Weight (after) 20.8 22.4 21.7 23.6 19.6 19.9 20.8 22.5 21.5 23.7 19.5 19.8 1) Find the standardized t test 2) Find the P-value 3) Decide whether to reject or fail to reject the null hypothesis. 4) Interpret the decision in the context of the original claim. 19,600For the distribution as shownDetermine the 3rd quartile Class. f3-6 46-9 109-12 1212-15 915-18 5
- A scientist claims that pneumonia causes weight loss in mice. The table shows the weights (in grams) of six mice before infection and two days after infection. At a= 0.10, is there enough evidence to support the scientist's claim? Assume the samples are random and dependent, and the population is normally distributed. Complete parts (a) through (e) below. 1 2 22.7 21.6 20.6 20.6 21.7 22.9 21.3 20.9 19.9 20.2 20.6 21.7 Mouse 3 4 56o Weight (before) Weight (after) (a) Identify the claim and state Ho and H, What is the claim? O A. Weight loss causes pneumonia in mice. O B. Pneumonia causes weight gain in mice. Yc. Pneumonia causes weight loss in mice. O D. Weight gain causes pneumonia in mice. Let Ha be the hypothesized mean of the difference in the weights (before - after). What are Ho and H,? O A. Ho: Hg s0 H H >0 OB. Ho: Ha sd OC. Ho: Ha0 OF. Ho: Hg zd OE. Ho: Ha =0 H Hg #0 OD. Ho: Ha0The following table gives profits (in ten thousands of shillings) of two supermarkets over a duration of one year. Determine which supermarket has a greater variability of its profits.The following graph illustrates 140 120 100 10 20 50 60 80 Multiple Choice О О a distribution for a single variable a positive or direct relationship a negative or inverse relationship no relationship
- N Career 1 Career 2 Career 3 1 59 72 58 2 43 79 49 3 55 81 60 4 53 86 47 Table 1 For Table 1, determine the following point estimates: The mathematical expectation. The variance. Root-mean-square deviation Correlation coefficient between X and Y. Correlation coefficient between X and Z. Correlation coefficient between Y and Z. The table values are in the image belowNeed help with this Intro to probability and statistics homework problem. Make sure your handwriting is neat and readable.A scientist claims that pneumonia causes weight loss in mice. The table shows the weights (in grams) of six mice before infection and two days after infection. At a = 0.10, is there enough evidence to support the scientist's claim? Assume the samples are random and dependent, and the population is normally distributed. Complete parts (a) through (e) below. 1 2 22.7 21.6 20.6 20.6 21.7 22.9 21.3 20.9 19.9 20.2 20.6 21.7 Mouse 3 4 56 e Weight (before) Weight (after) (a) Identify the claim and state Ho and H. What is the claim? O A. Weight loss causes pneumonia in mice. O B. Pneumonia causes weight gain in mice. O C. Pneumonia causes weight loss in mice. O D. Weight gain causes pneumonia in mice.
- 10 1.995, 2.266 70011160 OOOOO 22000601.340 4371381 2223 17 1.379 490 3051525 1992 Highest year of school completed Based on the boxplot which shows the distribution of years of education for American adults, we can conclude: the mean will be smaller than the median there are outliers at the higher end of the distribution the distribution is positively skewed all of the above none of the above4. The frequency distribution below gives the cost of production of sugarcane in holdings. Obtain the arithmetic mean. Cost of Production No. of Holdings Cost of Production No. of Holdings 2 - 6 1 18 – 22 52 6 - 10 9. 22 – 26 36 10 – 14 21 26 – 30 19 14 – 18 47 30 - 34 3X 6.3.10 Question Help Three randomly selected households are surveyed. The numbers of people in the households are 2, 4, and 9. Assume that samples of sizen=2 are randomly selected with replacement from the population of 2, 4, and 9. Construct a probability distribution table that describes the sampling distribution of the proportion of odd numbers when samples of sizes n= 2 are randomly selected. Does the mean of the sample proportions equal the proportion of odd numbers in the population? Do the sample proportions target the value of the population proportion? Does the sample proportion make a good estimator of the population proportion? Listed below are the nine possible samples. 2,2 2,4 2,9 4,2 4,4 4,9 9,2 9,4 9,9 Construct the probability distribution table. Sample Probability Proportion (Type an integer or fraction.)