First we calculate the current across each resistor. From Ohm's law, we arrive at a general formula for current: Plugging in values, the current across the resistor R1 is equal to: (Please note that the current is in milliamperes) mA Similarly the current across R2 is: 12 = mA And the current across R3 is: 13 = mA The current read by the ammeter is the sum of the currents across each resistor: 1=1+/2+13 | = mA Alternatively, we can solve for the current across the ammeter by first calculating the equivalent resistance and then applying Ohm's law. The equivalent resistance of the three resistors in parallel is: 1/Reg =1/R1+1/R2 +1/ Thus, Reg Ω

First we calculate the current across each resistor. From Ohm's law, we arrive at a general formula for current: Plugging in values, the current across the resistor R1 is equal to: (Please note that the current is in milliamperes) mA Similarly the current across R2 is: 12 = mA And the current across R3 is: 13 = mA The current read by the ammeter is the sum of the currents across each resistor: 1=1+/2+13 | = mA Alternatively, we can solve for the current across the ammeter by first calculating the equivalent resistance and then applying Ohm's law. The equivalent resistance of the three resistors in parallel is: 1/Reg =1/R1+1/R2 +1/ Thus, Reg Ω

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Question

First we calculate the current across each resistor. From Ohm's law, we arrive at a general formula for current:
Plugging in values, the current across the resistor R1 is equal to: (Please note that the current is in milliamperes)
mA
Similarly the current across R2 is:
12 =
mA
And the current across R3 is:
13 =
mA
The current read by the ammeter is the sum of the currents across each resistor:
|=l1+/2 +l3
| =
mA
Alternatively, we can solve for the current across the ammeter by first calculating the equivalent resistance and then applying
Ohm's law.
The equivalent resistance of the three resistors in parallel is:
1/Reg =1/R, +1/R2 + 1/
Thus,
Rea
Ω
%3D

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