First, review momentum conservation. A car with a mass of 2000 kg is stopped at a red light. Along comes a second car with a mass of 1200 kg and an initial speed 40 m/s, and WHAM!!!, it hits the car at rest. How fast did the cars go after the collision, assuming they were stuck together?

First, review momentum conservation. A car with a mass of 2000 kg is stopped at a red light. Along comes a second car with a mass of 1200 kg and an initial speed 40 m/s, and WHAM!!!, it hits the car at rest. How fast did the cars go after the collision, assuming they were stuck together?

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Concept explainers

Proper Length

The theory of special relativity explains the connection between space and time to objects that move in a straight line at a constant speed. The objects move at the speed of light. When an object approaches light speed, its mass is endless and cannot move faster than light. The most crucial postulate of Einstein's special relativity is that the laws of nature do not change in each frame of reference.

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Help Can you explain this and show me how to do it

ENERGY CONSERVATION
Solve the following problems and remember, SHOW ALL WORK ALL OF THE TIME! No
credit is given for answers without work shown.
First, review momentum conservation.
A car with a mass of 2000 kg is stopped at a red light. Along comes a second car with a mass of
1200 kg and an initial speed 40 m/s, and WHAM!!!, it hits the car at rest. How fast did the cars
go after the collision, assuming they were stuck together?
m, V + m, v21 = m, Vr + m, V2t
Or... remember that momentum is conserved and use p = m•v
A picture might help...
Label the drawing
before
m/sec
kg
kg
after

%3D
m,•vi + m,°V2i = m,•v1 + m2°V21
Or... remember that momentum is conserved and use p = m•v
A picture might help...
Label the drawing
before
m/sec
kg
kg
after
m/sec
kg
kg

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