Finding the work done in moving an object. Work Done by a Variable Force Along a Line. If a variable force F(x) moves an object in a positive direction along the z-axis from z = a to z = b, then the work done on the object is W F(z) dz Part 1. Setup the integral that will give the work done by a constant force, F = 12 lb, in moving a chair (along a line) a distance of 7 feet. %3D Note: Assume that initial position of the chair is at z = 0. Part 2. Calculate the done by the force described above. foot-pounds. Note: enter your answer as an exact value without using decimals.

Calculus: Early Transcendentals
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Author:James Stewart
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Chapter1: Functions And Models
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Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Finding the work done in moving an object.
Work Done by a Variable Force Along a Line.
If a variable force F(x) moves an object in a positive direction along the r-axis from z = a to z = b, then the work
done on the object is
= [ F(=) dz
W =
Part 1.
Setup the integral that will give the work done by a constant force, F = 12 lb, in moving a chair (along a line) a
distance of 7 feet.
W =
Note: Assume that initial position of the chair is at z = 0.
Part 2.
Calculate the done by the force described above.
w = foot-pounds.
Note: enter your answer as an exact value without using decimals.
Transcribed Image Text:Finding the work done in moving an object. Work Done by a Variable Force Along a Line. If a variable force F(x) moves an object in a positive direction along the r-axis from z = a to z = b, then the work done on the object is = [ F(=) dz W = Part 1. Setup the integral that will give the work done by a constant force, F = 12 lb, in moving a chair (along a line) a distance of 7 feet. W = Note: Assume that initial position of the chair is at z = 0. Part 2. Calculate the done by the force described above. w = foot-pounds. Note: enter your answer as an exact value without using decimals.
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