We start from the expression for the contact force 4 a³ 1/21 F=E (₁ 7² - (07*³²¹) ³²) '8γπa3 E* 3 R E* taking the derivative of this force with respect to the contact radius, a, and setting it equal to zero will give us the stationary points in the force versus contact radius response (see Figure 5.3) аг ½2 (4a² - (88x) ¹² 3 a ¹²²) R E* We can reduce this to 8 2 = 3 ak dividing both side by a¹/2, we obtain 8 3/2 = R which can be simplified to 3/2 = 887 112 12 3 (BYx) E* 1/2 १४ (98XR²) 22

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Author:James Stewart
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Chapter1: Functions And Models
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can someone explain this differentation to me please 

We start from the expression for the contact force
F = E*
4
3 R
(3775²) 1/²)
1
E*
taking the derivative of this force with respect to the contact radius, a, and setting it equal to zero
will give us the stationary points in the force versus contact radius response (see Figure 5.3)
½/2
OF
a
² (4a² - (80x) ¹² 3 α²²) =
(Brx
We can reduce this to
(BOA) ²
a½/2
=
а
3
dividing both side by a¹/2, we obtain
3/2
-
3 (Brx) 1²
a
which can be simplified to
3/2
(98xR²) 12/2
१४
ㅈ
a
E*
-
a
Transcribed Image Text:We start from the expression for the contact force F = E* 4 3 R (3775²) 1/²) 1 E* taking the derivative of this force with respect to the contact radius, a, and setting it equal to zero will give us the stationary points in the force versus contact radius response (see Figure 5.3) ½/2 OF a ² (4a² - (80x) ¹² 3 α²²) = (Brx We can reduce this to (BOA) ² a½/2 = а 3 dividing both side by a¹/2, we obtain 3/2 - 3 (Brx) 1² a which can be simplified to 3/2 (98xR²) 12/2 १४ ㅈ a E* - a
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