Find y(t) solution of the initial value problem y" + 6y +9y= u(t-3) e³(t-3), y(0) = 0, y'(0) = 0, where u(t) is the step function. 1 y(t) = -te y(t) = u(t − 3) / (t – y(t) = e 6 - 1 6 (t-3) e³(t-3) -3t 1 36 te-3t

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A: It is differential equation problem

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