Find y(t) solution of the initial value problem ty' - y + 5t² cos(3t) = 0, None of the options displayed. y(t) = t cos(3t) y(t) y(t) = 5 3 5 t (1 - sin(3t)) t cos(3t) 3 | y(t) = t (1 — sin(3t)) Oy(t) = cos(3t) Oy(t) = 1 - sin(3t) y (7)=0, t>0.

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Find y(t) solution of the initial value problem
ty' − y + 5t² cos(3t) = 0, y(7)
6
None of the options displayed.
y(t) = t cos(3t)
y(t)
=
y(t) =
=
5
3
5
t (1 – sin(3t))
t cos(3t)
3
| y(t) = t (1 — sin(3t))
| y(t) = cos(3t)
| y(t) = 1 — sin(3t)
-
=
0,
t> 0.
Transcribed Image Text:Find y(t) solution of the initial value problem ty' − y + 5t² cos(3t) = 0, y(7) 6 None of the options displayed. y(t) = t cos(3t) y(t) = y(t) = = 5 3 5 t (1 – sin(3t)) t cos(3t) 3 | y(t) = t (1 — sin(3t)) | y(t) = cos(3t) | y(t) = 1 — sin(3t) - = 0, t> 0.
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