If we use the variation of parameters for the equation y"+ y = tan(t) by solving uj cos(t) + ug sin(t) = 0 - uj sin(t) + uz cos(t) = tan(t) what do we get for u1? sin(t) - In sec(t) + tan(t) O u1 -cos(t) = In O u1 sin(t) sin (t) cos(t)
If we use the variation of parameters for the equation y"+ y = tan(t) by solving uj cos(t) + ug sin(t) = 0 - uj sin(t) + uz cos(t) = tan(t) what do we get for u1? sin(t) - In sec(t) + tan(t) O u1 -cos(t) = In O u1 sin(t) sin (t) cos(t)
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Question
![If we use the variation of parameters for the equation y+y = tan(t) by solving
uj cos(t) + ug sin(t) 0
- uj sin(t) + ub cos(t) = tan(t)
what do we get for u1?
Uj =
sin(t)
In sec(t) + tan(t)
U1 =
cos(t)
sin(t)
= In
sin (t)
cos t)
U1 =](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F7ff6645e-3de1-4ab7-aa92-8a7878592fee%2F20e07050-5499-4dd0-ba6b-c52b4e535a73%2F1t24srf_processed.jpeg&w=3840&q=75)
Transcribed Image Text:If we use the variation of parameters for the equation y+y = tan(t) by solving
uj cos(t) + ug sin(t) 0
- uj sin(t) + ub cos(t) = tan(t)
what do we get for u1?
Uj =
sin(t)
In sec(t) + tan(t)
U1 =
cos(t)
sin(t)
= In
sin (t)
cos t)
U1 =
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