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Find values for b such that the triangle has one solution, two solutions (if possible), and no solution. A= 32°, am 9 (a) one solution 9. O b- 9, b> sin(32") O 9 sin(32°) (b) two solutions (if possible) O ba 9, b > 6. sin(32) O 9 sin(32) (c) no solution Ob9, b > sin(32 sin(32)

Find values for b such that the triangle has one solution, two solutions (if possible), and no solution. A= 32°, am 9 (a) one solution 9. O b- 9, b> sin(32") O 9 sin(32°) (b) two solutions (if possible) O ba 9, b > 6. sin(32) O 9 sin(32) (c) no solution Ob9, b > sin(32 sin(32)

Elementary Geometry For College Students, 7e
Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
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Find values for b such that the triangle has one solution, two solutions (if possible), and no solution. A = 32°, a =9 (a) one solution 9. O b= 9, b> sin(32°) 9. O 9 <b< sin(32°) 9. O b's 9, b sin(32°) Ob< sin(32°) 9. O b> sin(32°) (b) two solutions (if possible) O b= 9, b> 6. sin(32°) O 9<b< sin(32) Obs 9, b = sin(32°) Obs sin(329) O b> sin(329) (c) no solution O b= 9, b> sin(32) sin(32)
Transcribed Image Text:Find values for b such that the triangle has one solution, two solutions (if possible), and no solution. A = 32°, a =9 (a) one solution 9. O b= 9, b> sin(32°) 9. O 9 <b< sin(32°) 9. O b's 9, b sin(32°) Ob< sin(32°) 9. O b> sin(32°) (b) two solutions (if possible) O b= 9, b> 6. sin(32°) O 9<b< sin(32) Obs 9, b = sin(32°) Obs sin(329) O b> sin(329) (c) no solution O b= 9, b> sin(32) sin(32)
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