Find values for b such that the triangle has one solution, two solutions (if possible), an A 125°, a = 204 (a) one solution Ob = 204 O 204 < b < Ob< Ob < 204 Ob> Ob< 204 sin (125°) 204 sin(125°) (b) two solutions (if possible) 204 204 < b < sin(125°) Obe 204 sin(125°) 204 sin(125°) 204 sin(125°) Obs 204, b = O not possible 204 sin(125°)

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