b) Using the equation 3 sin² x + 7 sin x = cos²x - 4 i) ii) Hence solve, for 0 < x < 360° Show that the equation can be written in the form: 4sin2x + 7sinx + 3 = 0. 3sin²x + 7sinx= cos2x - 4 2 4
b) Using the equation 3 sin² x + 7 sin x = cos²x - 4 i) ii) Hence solve, for 0 < x < 360° Show that the equation can be written in the form: 4sin2x + 7sinx + 3 = 0. 3sin²x + 7sinx= cos2x - 4 2 4
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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![b) Using the equation 3 sin² x + 7 sin x = cos²x - 4
i)
ii) Hence solve, for 0 < x < 360°
Show that the equation can be written in the form:
4sin2x + 7sinx + 3 = 0
3sin²x + 7sinx = cos2x - 4
2
4](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F18ed0ce2-6c58-45bd-98cf-399128f062f8%2Fa19e41c9-5c72-432c-aed4-e7330482e891%2Fo1d7n4u_processed.jpeg&w=3840&q=75)
Transcribed Image Text:b) Using the equation 3 sin² x + 7 sin x = cos²x - 4
i)
ii) Hence solve, for 0 < x < 360°
Show that the equation can be written in the form:
4sin2x + 7sinx + 3 = 0
3sin²x + 7sinx = cos2x - 4
2
4
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