Find u · (v x w). This quantity is called the triple scalar product of u, v, and w. u = k, v = j, w = 2i
Find u · (v x w). This quantity is called the triple scalar product of u, v, and w. u = k, v = j, w = 2i
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Question
![**Triple Scalar Product**
To solve for \( \mathbf{u} \cdot (\mathbf{v} \times \mathbf{w}) \), known as the triple scalar product of \(\mathbf{u}\), \(\mathbf{v}\), and \(\mathbf{w}\), we use the following vector assignments:
- \(\mathbf{u} = \mathbf{k}\)
- \(\mathbf{v} = \mathbf{j}\)
- \(\mathbf{w} = 2\mathbf{i}\)
**Step-by-step Explanation:**
1. **Vector Cross Product:**
- Calculate \(\mathbf{v} \times \mathbf{w}\).
- Since \(\mathbf{v} = \mathbf{j}\) and \(\mathbf{w} = 2\mathbf{i}\), the cross product \(\mathbf{j} \times (2\mathbf{i})\) results in the vector \(-2\mathbf{k}\).
2. **Dot Product:**
- Compute \(\mathbf{u} \cdot (-2\mathbf{k})\).
- Since \(\mathbf{u} = \mathbf{k}\), the dot product \(\mathbf{k} \cdot (-2\mathbf{k})\) equals \(-2\).
Therefore, the triple scalar product is \(-2\).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fcffe6fb8-a8b1-4738-951c-b41ccaeecf4e%2F6da974f8-290e-44df-a3c4-f2b0c3bc6abb%2Fzdxg5wa_processed.png&w=3840&q=75)
Transcribed Image Text:**Triple Scalar Product**
To solve for \( \mathbf{u} \cdot (\mathbf{v} \times \mathbf{w}) \), known as the triple scalar product of \(\mathbf{u}\), \(\mathbf{v}\), and \(\mathbf{w}\), we use the following vector assignments:
- \(\mathbf{u} = \mathbf{k}\)
- \(\mathbf{v} = \mathbf{j}\)
- \(\mathbf{w} = 2\mathbf{i}\)
**Step-by-step Explanation:**
1. **Vector Cross Product:**
- Calculate \(\mathbf{v} \times \mathbf{w}\).
- Since \(\mathbf{v} = \mathbf{j}\) and \(\mathbf{w} = 2\mathbf{i}\), the cross product \(\mathbf{j} \times (2\mathbf{i})\) results in the vector \(-2\mathbf{k}\).
2. **Dot Product:**
- Compute \(\mathbf{u} \cdot (-2\mathbf{k})\).
- Since \(\mathbf{u} = \mathbf{k}\), the dot product \(\mathbf{k} \cdot (-2\mathbf{k})\) equals \(-2\).
Therefore, the triple scalar product is \(-2\).
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