**Text Description:**Title: Finding Z-scores for the Middle 72% of a Standard Normal Distribution**Instructions:**- Find the Z-scores that separate the middle 72% of the distribution from the area in the tails of the standard normal distribution.- Click the icon to view a table of areas under the normal curve.**Input Area:**- The Z-scores are [________]. *(Use a comma to separate answers as needed. Round to two decimal places as needed.)***Options:**- Help me solve this- View an example- Get more help**Table of Areas Under the Normal Curve:**The table provides cumulative probabilities for the standard normal distribution:- The rows and columns indicate the Z-values, and the body of the table shows the area to the left of a given Z-value under the normal curve.- For example, to find the area for Z = 0.3, locate the row for 0.3 and the column for 0.00, and the intersecting value is the cumulative probability.**Graph/Diagram Description:**- The table is a standard Z-table, displaying cumulative probabilities for different Z-scores.- The rows correspond to the first decimal of the Z-score, ranging from -0.0 to 3.4.- The columns add additional precision, ranging from .00 to .09.- Values inside the table represent the probability that a value is less than the corresponding Z-score.*Note: Adjust the Z-scores as needed to find the correct values separating the middle 72% from the tails.* ### Understanding Z-Scores for the Normal DistributionTo find the Z-scores that separate the middle 72% of a standard normal distribution from the tails:1. **Problem Statement:** - Determine the Z-scores that divide the middle 72% of the distribution from the two tails. - Use a standard normal distribution table and round your answers to two decimal places.2. **Using the Table:** - Refer to the "Tables of areas under the normal curve" provided in the image. - This table helps find the area under the curve for different Z-score values.3. **Diagram Explanation:** - The image includes a small bell curve showing the area in question (the 72% in the center). - The table (Table V) provides cumulative probabilities for Z-scores ranging from -3.4 to 3.4.4. **How to Read the Table:** - The leftmost column lists Z-scores from -3.4 to 3.4. - The top row represents the decimal extension of the Z-scores (e.g., .00, .01, etc.). - Cross-referencing a Z-score and its decimal expansion gives the cumulative probability from the left tail.5. **Steps to Solve:** - Identify cumulative probabilities corresponding to the lower and upper bounds of the middle 72%. - For the standard normal distribution, the total area is 1. The middle 72% means 0.72 is centrically distributed, leaving (1 - 0.72) / 2 = 0.14 in each tail. - Look for the Z-score where the cumulative probability is 0.14 for the lower Z and 0.86 (1 - 0.14) for the upper Z.6. **Practical Application:** - These Z-scores define critical regions in hypothesis testing and set thresholds for statistical decision-making.### Interactive Features:- **Help Options:** - "Help me solve this" links to guided solutions. - "View an example" provides similar problems with solutions. - "Get more help" offers additional resources or explanations. - **Print and Done Buttons:** - These allow you to print the table or close the window once the task is complete. Use this framework to determine precise Z-scores for your statistical analysis needs, ensuring a comprehensive understanding of data distribution

According to the given information, we have The distribution used is standard normal distribution.We know that, Z-scores that seperates the middle 72% of the distribution from the area in the tails of the standard normal distribution is given by, P(-z<Z<z)=0.72 ...... Equation (1)⇒P(Z<z)-P(Z<-z)=0.72We know that, P(Z<-z)=1-P(Z<z)Now,⇒P(Z<z)-1-P(Z<z)=0.72⇒P(Z<z)-1+P(Z<z)=0.72⇒2P(Z<z)-1=0.72⇒2P(Z<z)=0.72+1⇒2P(Z<z)=1.72⇒P(Z<z)=1.722⇒P(Z<z)=0.86 Now, Z score at p-value(0.86) and left tailed is 1.08 i.e. z = 1.08 Now, putting the value of z in equation (1), we haveP(-1.08<Z<1.08)=0.72 Therefore, The z scores are -1.08, 1.08 Answer = -1.08, 1.08 (Round to two decimal places) Thank you..!!