Find the volume of the solid generated by revolving the region bounded by y = 2x, y=0, x=0, and x = 4 about the x-axis. The volume of the solid generated is cubic units. (Type an exact answer, using as needed.)

Calculus: Early Transcendentals
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ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
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**Problem Statement**

Find the volume of the solid generated by revolving the region bounded by \( y = 2x \), \( y = 0 \), \( x = 0 \), and \( x = 4 \) about the x-axis.

---

**Answer Section**

The volume of the solid generated is \( \boxed{\quad } \) cubic units.
(Type an exact answer, using \(\pi\) as needed.)

---

**Detailed Explanation**

To elaborate on this problem, consider the process of integrating to find the volume of a solid of revolution. The region defined by the given boundaries is rotated around the x-axis. 

1. **Function and Boundaries**:
    - The function \( y = 2x \) specifies the upper boundary of the region. 
    - The x-axis \( y = 0 \) serves as the lower boundary.
    - The vertical lines \( x = 0 \) (left boundary) and \( x = 4 \) (right boundary) provide the limits for the x-values.

2. **Integration Setup**:
    - The volume of a solid of revolution can be calculated using the disk method, where the volume \( V \) is given by the integral:
      \[
      V = \pi \int_{a}^{b} [f(x)]^2 \, dx
      \]
    - In this case, \( f(x) = 2x \), and the limits of integration are from \( x = 0 \) to \( x = 4 \). Therefore, the volume integral becomes:
      \[
      V = \pi \int_{0}^{4} (2x)^2 \, dx
      \]

3. **Simplify the Integral**:
    - Simplify the integrand:
      \[
      V = \pi \int_{0}^{4} 4x^2 \, dx
      \]

4. **Calculate the Definite Integral**:
    - Integrate \( 4x^2 \):
      \[
      V = 4\pi \int_{0}^{4} x^2 \, dx = 4\pi \left[ \frac{x^3}{3} \right]_{0}^{4}
      \]
    - Evaluate the definite integral:
      \[
      V = 4\pi \left( \frac{4^3}{3} - \frac{
Transcribed Image Text:**Problem Statement** Find the volume of the solid generated by revolving the region bounded by \( y = 2x \), \( y = 0 \), \( x = 0 \), and \( x = 4 \) about the x-axis. --- **Answer Section** The volume of the solid generated is \( \boxed{\quad } \) cubic units. (Type an exact answer, using \(\pi\) as needed.) --- **Detailed Explanation** To elaborate on this problem, consider the process of integrating to find the volume of a solid of revolution. The region defined by the given boundaries is rotated around the x-axis. 1. **Function and Boundaries**: - The function \( y = 2x \) specifies the upper boundary of the region. - The x-axis \( y = 0 \) serves as the lower boundary. - The vertical lines \( x = 0 \) (left boundary) and \( x = 4 \) (right boundary) provide the limits for the x-values. 2. **Integration Setup**: - The volume of a solid of revolution can be calculated using the disk method, where the volume \( V \) is given by the integral: \[ V = \pi \int_{a}^{b} [f(x)]^2 \, dx \] - In this case, \( f(x) = 2x \), and the limits of integration are from \( x = 0 \) to \( x = 4 \). Therefore, the volume integral becomes: \[ V = \pi \int_{0}^{4} (2x)^2 \, dx \] 3. **Simplify the Integral**: - Simplify the integrand: \[ V = \pi \int_{0}^{4} 4x^2 \, dx \] 4. **Calculate the Definite Integral**: - Integrate \( 4x^2 \): \[ V = 4\pi \int_{0}^{4} x^2 \, dx = 4\pi \left[ \frac{x^3}{3} \right]_{0}^{4} \] - Evaluate the definite integral: \[ V = 4\pi \left( \frac{4^3}{3} - \frac{
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