Find the values of the unknowns using any method applicable.5а + 2b — 6с+ 4d — е %3D 62а — b — с — d %3D —13Ь + 3с + d 3D 0За + 4b — 1.5с + 5d + e %3 4|a + b + c + d + e = 1

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Answered: Find the values of the unknowns using…

Algebra & Trigonometry with Analytic Geometry

13th Edition

ISBN:9781133382119

Author:Swokowski

Publisher:Swokowski

Chapter9: Systems Of Equations And Inequalities

Section9.1: Systems Of Equations

Problem 6E

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EVALUATION. Matching Type. Match Column A with Column B. Write the letter of your choice from Column B in the blank before each item number. Column A Column B 1. у %3D х2 + 2х —3 at (-2,-3) а. 6 2. y = 2x2 – 3x + 1 at (2,3) b. 5 3. y = x2 – 4x + 1 at (2, –3) С. -2 4. y = 3x² + 4x at (1, 7) d. 0 5. y = 3x2 + 2 at (1,5) е. 10
Determine whether the ordered pair (9,4) is a solution of the equation 10x−y−86=0. Since the expression 10x−y−86 evaluated at (9,4) is Blank,(9,4)▼is or not a solution. Determine whether (6,8) is a solution of (x+4)2+(y+4)2=240. Since the expression (x+4)2+(y+4)2 evaluated at (6,8) is Blank,(6,8) ▼is or not a solution.
find the value of the variables 4/5a = -20-2b = 6 -9b = 242 = 6k 5 = 10k -16 = -4k-3b = -9 -9=e/3 5=-e/32p + 5 = 13 3p - 5 = 13 4p + 2 = 2260 = 6t + 12. 12 = 3r - 9…
2x - 3x -2 6x + 3x? + 2x +1 2x - 3x- 2 6x° + 3x + 2x + 1
Solve the following equations: 7х1 — 4х2 + Хз — 1 - -4x1 + 6x2 – 4x3 + X4 = 1 Xi-2 – 4Xj–1 +6x¡ – 4x¡+1 + Xi+2 = 1 (i= 3, 4, ..., 8) X7 – 4x8 + 6xg – 4x10 = 1 Хв — 4х9 + 7х10 1 -
6x2 -4x 1. Find the first-order derives: I. y = П. у %3D (2x3 + 7х - 14)5 4x2-8x+5
Consider the following two systems of equations: 5x1 + x2 – 3x3 — Зхз — 0 5х1 + X2 — Зхз — - 3x3 -9x1 + 2x2 + 5x3 = 1 -9x1 + 2x2 + 5x3 = 5 4x1 + x2 – 6x3 = 9 4.x1 + x2 – 6x3 = 45 = 45 It can be shown that the first system has a solution. Use this fact and the theory from this section to explain why the second system must also have a solution. (Make no row operations.)
6. Find the values of the unknowns using any method applicable. 5а + 2b — 6с + 4d — е %3D 6 2а- b —с — d 3 -1 3Ь + Зс + d %30 За + 4b — 1.5с + 5d +e %3D4 a + b + c +d + e = 1 a) Value of a b) Value of b c) Value of c d) Value of d e) Value of e
Subtract. (6x - 2x? + 5x- 8) - (4x° - 4x? - 3x + 2) (6x° - 2x? + 5x - 8) - (4x³ - 4x² - 3x +2) = D (Simplify your answer. Use integers or fractions for any numbers in the expression.)
Solve the system of equation below. Modulus of each unknown. Given : Зи + (1 — і)о + (3+ 4i)w 3 (4 + v3) (1 – i) (5+ 21)и — (6 + 2:)u — (2 + 5і)w %3 (-3 6V3 – 2v3) +i(66 – | 3iu + 5v + 2(1 + i)w= 5(1+ V3) 17i | Find: |w| – |v| – |u]. Your answer

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Find the values of the unknowns using any method applicable. 5а + 2b — 6с+ 4d — е %3D 6 2а — b — с — d %3D —1 3Ь + 3с + d 3D 0 За + 4b — 1.5с + 5d + e %3 4 | a + b + c + d + e = 1