Consider the following two systems of equations: 5x1 + x2 – 3x3 — Зхз — 0 5х1 + X2 — Зхз — - 3x3 -9x1 + 2x2 + 5x3 = 1 -9x1 + 2x2 + 5x3 = 5 4x1 + x2 – 6x3 = 9 4.x1 + x2 – 6x3 = 45 = 45 It can be shown that the first system has a solution. Use this fact and the theory from this section to explain why the second system must also have a solution. (Make no row operations.)

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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Consider the following two systems of equations:
5x1 + x2 – 3x3
— Зхз — 0
5х1 + X2 — Зхз —
- 3x3
-9x1 + 2x2 + 5x3 = 1
-9x1 + 2x2 + 5x3 = 5
4x1 + x2 – 6x3 = 9
4.x1 + x2 – 6x3 = 45
= 45
It can be shown that the first system has a solution. Use this fact and the theory from this section to explain why the
second system must also have a solution. (Make no row operations.)
Transcribed Image Text:Consider the following two systems of equations: 5x1 + x2 – 3x3 — Зхз — 0 5х1 + X2 — Зхз — - 3x3 -9x1 + 2x2 + 5x3 = 1 -9x1 + 2x2 + 5x3 = 5 4x1 + x2 – 6x3 = 9 4.x1 + x2 – 6x3 = 45 = 45 It can be shown that the first system has a solution. Use this fact and the theory from this section to explain why the second system must also have a solution. (Make no row operations.)
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