Find the value of x. 15. 2x° 128

Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
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please help me answer questions 14 and 15
### Geometry Problem: Find the Value of \( x \)

**Problem Statement:**
15. Find the value of \( x \).

**Diagram Explanation:**
The provided diagram shows two intersecting lines and a transversal. The angles formed at the intersection are labeled as follows:
- One angle is labeled \( 128^\circ \).
- The vertically opposite angle to this is labeled \( 2x^\circ \).

**Step-by-Step Solution:**
1. Recognize that vertically opposite angles are equal. Therefore:
   \[
   2x^\circ = 128^\circ
   \]

2. Solve for \( x \):
   \[
   x = \frac{128^\circ}{2} = 64^\circ
   \]

**Conclusion:**
The value of \( x \) is \( 64^\circ \).
Transcribed Image Text:### Geometry Problem: Find the Value of \( x \) **Problem Statement:** 15. Find the value of \( x \). **Diagram Explanation:** The provided diagram shows two intersecting lines and a transversal. The angles formed at the intersection are labeled as follows: - One angle is labeled \( 128^\circ \). - The vertically opposite angle to this is labeled \( 2x^\circ \). **Step-by-Step Solution:** 1. Recognize that vertically opposite angles are equal. Therefore: \[ 2x^\circ = 128^\circ \] 2. Solve for \( x \): \[ x = \frac{128^\circ}{2} = 64^\circ \] **Conclusion:** The value of \( x \) is \( 64^\circ \).
**Problem 14.**

Given a triangle with the following properties:
- One of the angles is 43°.
- The triangle is isosceles, as indicated by the two equal sides marked with a hash line.
- The angles opposite the equal sides are marked \( x \) and \( y \), respectively.

We need to find the values of \( x \) and \( y \).

**Analysis:**
In an isosceles triangle, the angles opposite the equal sides are equal. Hence, \( x = y \).

Additionally, the sum of all internal angles in a triangle is always \( 180^\circ \).

**Calculation:**
Let us denote the three angles of the triangle as \( 43^\circ \), \( x \), and \( y \). As established, \( x = y \).

Thus:
\[ x + y + 43^\circ = 180^\circ \]
Since \( x = y \), we replace \( y \) with \( x \), giving:
\[ x + x + 43^\circ = 180^\circ \]
\[ 2x + 43^\circ = 180^\circ \]
Subtracting \( 43^\circ \) from both sides, we get:
\[ 2x = 137^\circ \]
Dividing both sides by 2:
\[ x = 68.5^\circ \]

Since \( x = y \):
\[ y = 68.5^\circ \]

Therefore:
\[ x = 68.5 \]
\[ y = 68.5 \]
Transcribed Image Text:**Problem 14.** Given a triangle with the following properties: - One of the angles is 43°. - The triangle is isosceles, as indicated by the two equal sides marked with a hash line. - The angles opposite the equal sides are marked \( x \) and \( y \), respectively. We need to find the values of \( x \) and \( y \). **Analysis:** In an isosceles triangle, the angles opposite the equal sides are equal. Hence, \( x = y \). Additionally, the sum of all internal angles in a triangle is always \( 180^\circ \). **Calculation:** Let us denote the three angles of the triangle as \( 43^\circ \), \( x \), and \( y \). As established, \( x = y \). Thus: \[ x + y + 43^\circ = 180^\circ \] Since \( x = y \), we replace \( y \) with \( x \), giving: \[ x + x + 43^\circ = 180^\circ \] \[ 2x + 43^\circ = 180^\circ \] Subtracting \( 43^\circ \) from both sides, we get: \[ 2x = 137^\circ \] Dividing both sides by 2: \[ x = 68.5^\circ \] Since \( x = y \): \[ y = 68.5^\circ \] Therefore: \[ x = 68.5 \] \[ y = 68.5 \]
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