Find the following probabilities. It may help to sketch the pdf for Standard Normal Distribution and shade in the area that corresponds to the probability of interest. 1) Z~ Norm(0, 1), find Pr(Z ≤ 1.78) 2) Z~ Norm(0, 1), find Pr(Z > 1.96) 3) Z~ Norm(0, 1), find Pr(-2.34 ≤Z < 1.45) 4) Z~ Norm(0, 1), find Pr(Z < -0.67) 5) Z~ Norm(0, 1), find Pr(Z = 2.3) 6) Z~ Norm(0, 1), find Pr(Z2-2.98) Do the same for the following below. Note however that they are no longer Standard Normal Distributions. 7) X~ Norm(266, 162), find Pr(X<200) 8) X~ Norm(-2, 52), find Pr(-4 < X <-3) 9) X Norm(-2, 52), find Pr(X=-3) 10) X~ Norm(64.4, 2.42), find Pr(|X| >70)

Q: (-5-20-100 to

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Q: 2= c2  + c

A: 2=C2+C We need to solve the equation.

Q: 17x - 91- 3> -6 17x -6

A: Given: 7x-9-3≥-6 To Find: To solve the given inequalities

Q: whats 7+1?

A: Given query is to add two numbers.

Q: Find a2, a3, a4, a1= -3,  an= 10+2an-1

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Q: 8+9-10

A: Given that                                            8+9-10 here we will use BODMAS B= Bracket  O=…

Q: a]3+20-2c doc

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Q: -3+9x=12

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Q: (-3,9) (-3,-5)

A: In (-3,9) and  (-3,-5) x ordinate = -3 for both.So on the line joining them x is fixed.

Q: a2-7a+10=0

A: We have to factor 10 so that the sum of the factors = -710= -5 times -2 and -5 + (-2) =-7 too So we…

Q: 20+(-4)(-5)

A: The calculation for 20+(-4)(-5) is presented as follows:

Q: 13t - 7 - 10t = 2

A:

Q: -9 -3 -2 -6 3- 6. -4 -6 -8- -10+

A: Given,    The graph is shown below:

Q: 3x-12= 99

A:

Q: 13-2+3

A: this is a simple calculation question we will simplify this by normal calculation.

Q: -5+2(8-12)

A: Use PEMDAS rule to simplify.First we work with the parenthesis. In it 8-12=-4

Q: Зх3 — 2х2 —6х + 4

A: a. Factorization, 3x3-2x2-6x+4=3x3-2x2-6x-4=x23x-2-23x-2=x2-23x-2

Q: 7 - 5 (10+8x)=37

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Q: - 6 = r-6. 3C

A: The given expression is: x-6=x-6

Q: x4-102=-9

A: Solve the given equation as follows. x4-102=-9x4-100=-9x4=100-9x4=91x22=91