Find the two x-intercepts of the function f and show that f '(x) = 0 at some point between the two x-intercepts. f(x)=x²-3x - 18 (x, y) = (-3,0 (x, y) = (6,0 ) (smaller x-value) ) (larger x-value) Find a value of x such that f '(x) = 0. x = 32 x

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