Find the total resistance of a 10km section of #20 AWG copper wire. Giv the diameter of the wire is 811 x 10-6 m and the area is 517.62 x 10⁹ m² 2 esistivity of copper is 17.2 n*m.
Find the total resistance of a 10km section of #20 AWG copper wire. Giv the diameter of the wire is 811 x 10-6 m and the area is 517.62 x 10⁹ m² 2 esistivity of copper is 17.2 n*m.
Introductory Circuit Analysis (13th Edition)
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Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
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![**Problem Statement: Calculating Resistance of a Copper Wire**
**Objective:**
Determine the total resistance of a 10 km section of #20 AWG copper wire.
**Given Data:**
- Diameter of the wire: \(811 \times 10^{-6}\) meters
- Cross-sectional area of the wire: \(517.62 \times 10^{-9}\) square meters
- Resistivity of copper: \(17.2 \, \text{n}\Omega \cdot \text{m}\)
**Task:**
Use the given parameters to find the resistance of the copper wire. The formula for calculating resistance (\(R\)) is:
\[
R = \rho \frac{L}{A}
\]
Where:
- \( R \) is the resistance in ohms (\(\Omega\)),
- \( \rho \) is the resistivity of the material (\(\Omega \cdot \text{m}\)),
- \( L \) is the length of the wire (meters),
- \( A \) is the cross-sectional area (m\(^2\)).
**Note:** Ensure to convert units where necessary for consistency in calculations.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F308db737-7862-446c-973d-78bf4e1d9584%2F59a6a5f4-c0c9-4be0-a514-fd397f4b6d2e%2Fi5st6yg_processed.png&w=3840&q=75)
Transcribed Image Text:**Problem Statement: Calculating Resistance of a Copper Wire**
**Objective:**
Determine the total resistance of a 10 km section of #20 AWG copper wire.
**Given Data:**
- Diameter of the wire: \(811 \times 10^{-6}\) meters
- Cross-sectional area of the wire: \(517.62 \times 10^{-9}\) square meters
- Resistivity of copper: \(17.2 \, \text{n}\Omega \cdot \text{m}\)
**Task:**
Use the given parameters to find the resistance of the copper wire. The formula for calculating resistance (\(R\)) is:
\[
R = \rho \frac{L}{A}
\]
Where:
- \( R \) is the resistance in ohms (\(\Omega\)),
- \( \rho \) is the resistivity of the material (\(\Omega \cdot \text{m}\)),
- \( L \) is the length of the wire (meters),
- \( A \) is the cross-sectional area (m\(^2\)).
**Note:** Ensure to convert units where necessary for consistency in calculations.
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