Find the total magnetic force acting on the loop abc.CcB60b.O a.F= 2ILB cos(60): downOb. F ILB; to the rightOc.F= ILB cos(60): upO d. F=ILB sin(60); to the leftF = ILB sin(60); into the pageF = 0O e.O f.g.F = 2ILB cos(60); out of the pageh.F = ILB sin(60); to the right

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Find the totạl magnetic force acting on the loop abc. L. 60 a b. a. F=2ILB cos(60): down %3D O b. F=ILB; to the right F= ILB cos(60): up O d. F=ILB sin(60); to the left O e. F=ILB sin(60); into the page Of F=0 g. F=2ILB cos(60); out of the page O h. F=ILB sin(60); to the right

Find the totạl magnetic force acting on the loop abc. L. 60 a b. a. F=2ILB cos(60): down %3D O b. F=ILB; to the right F= ILB cos(60): up O d. F=ILB sin(60); to the left O e. F=ILB sin(60); into the page Of F=0 g. F=2ILB cos(60); out of the page O h. F=ILB sin(60); to the right

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Concept explainers

Magnetic Field Of Coaxial Cable

The word coaxial means same axis. So for a long straight cable to be coaxial, it must have concentric cylindrical shaped conductor around it. Coaxial cable (popularly called ‘coax’) has various applications ranging from current conductors to radiofrequency signal transmitters. This cable has lower emission losses and provides protection from electromagnetic interference which allows signals with less power to transmit over longer distances.For example, currents produced in the pickup of a stereo turntable generally travel to the amplifier through a coaxial cable.The self-inductance of a coaxial cable is another important characteristic, because it influences the propagation of electrical signals in the cable.

Question

Find the total magnetic force acting on the loop abc.
Cc
B
60
b.
O a.
F= 2ILB cos(60): down
Ob. F ILB; to the right
Oc.
F= ILB cos(60): up
O d. F=ILB sin(60); to the left
F = ILB sin(60); into the page
F = 0
O e.
O f.
g.
F = 2ILB cos(60); out of the page
h.
F = ILB sin(60); to the right

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