Find the total change in the internal energy of a gas that is subjected to the following two-step process. In the first step the gas is made to go through isochoric heating until it gains 5863 J and its pressure is 3.32 x 10° Pa. In the second step it is subjected to isobaric adiabatic compression until its volume decreases by 7.50 x 103 m3. What is the total change in internal energy of this gas?
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- Find the total change in the internal energy of a gas that is subjected to the following two-step process. In the first step the gas is made to go through isochoric heating until it gains 5363 J and its pressure is 3.32 x 10° Pa. In the second step it is subjected to isobaric adiabatic compression until its volume decreases by 6.90 x 10 m³. What is the total change in internal energy of this gas?An ideal gas initially at 340 K undergoes an isobaric expansion at 2.50 kPa. The volume increases from 1.00 m3 to 3.00 m3 and 12.6 kJ is transferred to the gas by heat. (a) What is the change in internal energy of the gas? kJ (b) What is the final temperature of the gas? KFind the total change in the internal energy of a gas that is subjected to the following two-step process. In the first step the gas is made to go through isochoric heating until it gains 5863 J and its pressure is 4.12 x 10° Pa. In the second step it is subjected to isobaric adiabatic compression until its volume decreases by 7.90 x 10 m³. What is the total change in internal energy of this gas?
- Question B: A sample of 1.00 mole of a diatomic ideal gas is initially at temperature 265 K and volume 0.200 m3. The gas first undergoes an isobaric expansion, such that its temperature increases by 110.0 K. It then undergoes an adiabatic expansion so that its final volume is 0,440 m3. i. Sketch a PV diagram for the two-step process, including labeled initial, final, and intermediate states, and a two-part curve/path with an arrow indicating direction. Label the initial state "i", the final state "f", and the intermediate state "b". Write down the known values for P, T, and V at each point, e.g. T; = 265 K, and Th = 375 K. (B.1) What is the initial pressure of the gas, Pi, in pascals [Pa]? Pi = Pa Enter a number. (B.2) What is the total heat transfer, Q, to the gas, in joules [J]? Q = Qtotal = (B.3) What is the total work done on the gas, w, in joules [J]? w = Wtotal = Enter your answer for problem (B.3) for credit. First, use the following questions as intermediate steps; answers can…Find the total change in the internal energy of a gas that is subjected to the following two-step process. In the first step the gas is made to go through isochoric heating until it gains 5863 J and its pressure is 3.72 x 10° Pa. In the second step it is subjected to isobaric adiabatic compression until its volume decreases by 7.50 x 103 m³. What is the total change in .internal.energy.,of this gas? Enter a number. Finition of isochoric and isobaric processes. What is the work done during each process? JThe PV diagram shows the compression of 40.9 moles of an ideal monoatomic gas from state A to state B. Calculate Q, the heat added to the gas in the process A to B. Data: PA= 1.90E+5 N/m2 VA= 1.83E+0 m3 PB= 1.01E+5 N/m2 VB= 8.90E-1 m3›44
- A gas in a cylinder is held at a constant pressure of 2.20×105 Pa and is cooled and compressed from 1.90 m3 to 1.10 m3 . The internal energy of the gas decreases by 1.15×105 J. a) Find the work done by the gas. Express your answer in joules b)Find the amount of the heat that flowed into or out of the gas. Express your answer in joules to two significant figures. c) State the direction (inward or outward) of the flow.Find the total change in the internal energy of a gas that is subjected to the following two-step process. In the first step the gas is made to go through isochoric heating until it gains 5963 J and its pressure is 2.72 105 Pa. In the second step it is subjected to isobaric adiabatic compression until its volume decreases by 7.30 10-3 m3. What is the total change in internal energy of this gas?Please help me
- A sealed cylinder has a piston and contains 8.90×103 cm3 of an ideal gas at a pressure of 7.50 atm. Heat is slowly introduced, and the gas isothermally expands to 1.70×104 cm3. How much work ? does the gas do on the piston?A particular thermodynamic cycle acting on a monatomic ideal gas (y = 1.67) includes an isobaric expansion, an isochoric cooling, and then a isothermic contraction. The PV diagram is shown in the image below. P V The isobaric expansion occurs at a pressure of 1.8 × 105 Pa and changes the volume of the gas from 6.7 x 10-2 m³ to 13.08 × 102m³. What is the efficiency of the process?An ideal monatomic gas undergoes changes in pressure and volume, as shown in the pV diagram below. The initial volume is 0.02 m3 and the final volume is 0.10 m3. The initial pressure is 1 atm and the final pressure is 2 atm. Recall that 1 atm = 101.3 kPa. (a) Calculate the magnitude, or absolute value, of the work done on the gas in this process. Answer = - 13429J (c) The initial temperature of the gas is 308 K. Calculate the temperature of the gas at the end of the process. Answer = 3080 k Just need answer with the following: (d) What is the change in thermal energy for the gas in this process? (e) Calculate the quantity of heat transfer added to (positive) or removed from (negative) the gas during this process.