Find the time-domain expression corresponding to each phasor: a. V = 18.6/-54°V. b. I (20/45° - 50/-30°) mA. = 20+j80 - 30/15°) V. c. V = K

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Find the time-domain expression corresponding to each phasor:
a. V = 18.6/-54°V.
b. I = (20/45° - 50/-30°) mA.
-
c. V = (20 + j80 – 30/15°) V.
Transcribed Image Text:Find the time-domain expression corresponding to each phasor: a. V = 18.6/-54°V. b. I = (20/45° - 50/-30°) mA. - c. V = (20 + j80 – 30/15°) V.
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The answer should be in cos not sin. The degrees are correct though. Please fix and show how to correctly come to the answer so I can understand the steps. 

 

a. 18.6 cos (wt
b. 48.81 cos (wt
c. 72.79 cos (wt
54°) V;
+ 126.68°) mA;
+ 97.08°) V.
Transcribed Image Text:a. 18.6 cos (wt b. 48.81 cos (wt c. 72.79 cos (wt 54°) V; + 126.68°) mA; + 97.08°) V.
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