Find the third degree Taylor polynomial T3 (x)centered at a O T3 (x) = 3 - 6x + 9x² - 12x³ O T3 (x)=3- 3x² T3 (x) = 3 – 6(x − 1) + 18(x − 1)² – 72(x − 1)³ T3 (x) = 3 + 6(x − 1) + 9(x − 1)² + 12(x − 1)³ ○ T3 (x) = 3 – 6(x − 1) + 9(x − 1)² – 12(x − 1)³ O = 1 for the function f(x) = x²

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Find the third degree Taylor polynomial T3 (x)centered at a = 1 for the function f(x) =
-
○ T3(x) = 3 - 6x + 9x² 12x³
○ T3 (x) = 3 − 3x²
○ T3 (x) = 3 – 6(x − 1) + 18(x − 1)² – 72(x − 1)³
-
○ T3 (x) = 3 + 6(x − 1) + 9(x − 1)² + 12(x − 1)³
○ T3 (x) = 3 – 6(x − 1) + 9(x − 1)² – 12(x − 1)³
3
x²
Transcribed Image Text:Find the third degree Taylor polynomial T3 (x)centered at a = 1 for the function f(x) = - ○ T3(x) = 3 - 6x + 9x² 12x³ ○ T3 (x) = 3 − 3x² ○ T3 (x) = 3 – 6(x − 1) + 18(x − 1)² – 72(x − 1)³ - ○ T3 (x) = 3 + 6(x − 1) + 9(x − 1)² + 12(x − 1)³ ○ T3 (x) = 3 – 6(x − 1) + 9(x − 1)² – 12(x − 1)³ 3 x²
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