Find the third degree Taylor polynomial centered at c = 1 for the function. f(x) = √√x Select one: O a. O b. O c. O d. O e. 7 1 + 1 = √(x + 1) + 3/27 (x − 1)² - 128 1 + (x − 1) + 32 (x − 1)² - 1 + 1 = (x + 1) - 3/2 -(x-1)²+ 1+ (x-1)-3(x-1)² + 32 7 128 7 128 7 128 -(x − 1)³ (x+1)³ 7 1+ (x-1) - 32(x - 1)²³-128 (x+1)³ (x-1)³ -(x-1)³

Calculus: Early Transcendentals
8th Edition
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Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Find the third degree Taylor polynomial centered at c = 1 for the function.
f(x) = √x
Select one:
O a.
O b.
O d.
3
○ c. 1+ — (x+1)- 32 (x−1)² +
O e
7
1 +
- 1/² ( x + 1) + 3/2² (x − 1)² - 128
e.
3
1+ (x-1)+(x-1²-
/ -
32
1+
1+
(x-1)-3(x-1)² +
32
-(x + 1)³
7
128
7
128
7
128
-(x - 1)³
(x + 1)³
(x-1)³
10-1-0-1²-17 (x-1)²
- (x− 1)- 3/2 (x - 1)² - 128
Transcribed Image Text:Find the third degree Taylor polynomial centered at c = 1 for the function. f(x) = √x Select one: O a. O b. O d. 3 ○ c. 1+ — (x+1)- 32 (x−1)² + O e 7 1 + - 1/² ( x + 1) + 3/2² (x − 1)² - 128 e. 3 1+ (x-1)+(x-1²- / - 32 1+ 1+ (x-1)-3(x-1)² + 32 -(x + 1)³ 7 128 7 128 7 128 -(x - 1)³ (x + 1)³ (x-1)³ 10-1-0-1²-17 (x-1)² - (x− 1)- 3/2 (x - 1)² - 128
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