Find the standard molar enthalpy for the reaction C(s) + O₂(g) → CO(g) Given that: C(s) + O₂(g) →→ CO₂(g) → CO₂(g) → CO(g) + O2(g) AH = -394kJ ΔΗ = +283kJ Reaction 1 2 Reverse? Yes/No Multiply or Divide? If yes, by what?

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1.
Find the standard molar enthalpy for the reaction
C(s) + O₂(g) → CO(g)
Given that:
C(s) + O2(g) → CO₂(g) –
-394kJ
CO₂(g) → CO(g) + O2(g)
+283kJ
ΔΗ =
kJ
1
AH =
ΔΗ -
=
Transcribed Image Text:1. Find the standard molar enthalpy for the reaction C(s) + O₂(g) → CO(g) Given that: C(s) + O2(g) → CO₂(g) – -394kJ CO₂(g) → CO(g) + O2(g) +283kJ ΔΗ = kJ 1 AH = ΔΗ - =
Find the standard molar enthalpy for the reaction
C(s) + O₂(g) → CO(g)
Given that:
C(s) + O₂(g) → CO₂(g)
CO₂(g) → CO(g) + O2(g)
AH = -394k.J
AH = +283kJ
Reaction
1
2
Reverse? Multiply or
Yes/No
Divide?
If yes, by
what?
Transcribed Image Text:Find the standard molar enthalpy for the reaction C(s) + O₂(g) → CO(g) Given that: C(s) + O₂(g) → CO₂(g) CO₂(g) → CO(g) + O2(g) AH = -394k.J AH = +283kJ Reaction 1 2 Reverse? Multiply or Yes/No Divide? If yes, by what?
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