Find the standard equation of the circle whose center is on the line y = 3x - 3 and this circle cuts the a-axis at points (2, 0) and (4, 0). *
Find the standard equation of the circle whose center is on the line y = 3x - 3 and this circle cuts the a-axis at points (2, 0) and (4, 0). *
College Algebra (MindTap Course List)
12th Edition
ISBN:9781305652231
Author:R. David Gustafson, Jeff Hughes
Publisher:R. David Gustafson, Jeff Hughes
Chapter7: Conic Sections And Quadratic Systems
Section7.1: The Circle And The Parabola
Problem 1SC
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![Find the standard equation of the circle
whose center is on the line y= 3x - 3 and
this circle cuts the x-axis at points (2, 0)
and (4, 0).
(x-3) +(y+6)° = 37
(x-6)' +(y-3)' =37
(x- 3)° +(y-6)² = 37
....
(x+6)* +(y+3)° = 3](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe033c769-2863-4122-8b8e-4580d89a4059%2Fde51e274-6127-46ed-8e9c-173e2750367c%2Fw8mc9c_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Find the standard equation of the circle
whose center is on the line y= 3x - 3 and
this circle cuts the x-axis at points (2, 0)
and (4, 0).
(x-3) +(y+6)° = 37
(x-6)' +(y-3)' =37
(x- 3)° +(y-6)² = 37
....
(x+6)* +(y+3)° = 3
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