Find the standard deviation, s, of sample data summarized in the frequency distribution table below by using the formula below, where x represents the class midpoint f represents the class frequency, and n represents the total number of sample values. Also, compare the computed standard deviation to the standard deviation obtained from the original list of data values, 11.1. n(n - 1) Interval 20-26 27-33 34-40 41-47 48-54 55-61 62-68 Frequency 16 36 33 Standard deviation = (Round to one decimal place as needed.) Consider a difference of 20% between two values of a standard deviation to be significant. How does this computed value compare with the given standard deviation, 11.1? O A. The computed value is significantly greater than the given value. O B. The computed value is significantly less than the given value. OC. The computed value is not significantly different from the given value.

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**Find the Standard Deviation of Sample Data**

This exercise involves calculating the standard deviation, \( s \), of sample data summarized in a frequency distribution table using the formula below. In the formula, \( x \) represents the class midpoint, \( f \) is the class frequency, and \( n \) is the total number of sample values. You are also tasked with comparing the computed standard deviation to the standard deviation obtained from the original list of data values, which is 11.1.

**Formula for Calculating Standard Deviation:**

\[ s = \sqrt{\frac{n[\sum (f \cdot x^2)] - [\sum (f \cdot x)]^2}{n(n-1)}} \]

**Frequency Distribution Table:**

| Interval | Frequency |
|----------|-----------|
| 20-26    | 2         |
| 27-33    | 3         |
| 34-40    | 9         |
| 41-47    | 1         |
| 48-54    | 16        |
| 55-61    | 36        |
| 62-68    | 33        |

**Steps:**

1. **Enter the Computed Standard Deviation:** 
   - Round the answer to one decimal place as needed. Enter the result in the text box provided.

2. **Comparison to Given Standard Deviation:** 
   - Consider that a difference of 20% between two values of a standard deviation is deemed significant.
   - Analyze how the computed value compares with the provided standard deviation of 11.1.

**Options for Comparison:**

A. The computed value is significantly greater than the given value.

B. The computed value is significantly less than the given value.

C. The computed value is not significantly different from the given value.

**Instructions:** Click to select your answer(s).
Transcribed Image Text:**Find the Standard Deviation of Sample Data** This exercise involves calculating the standard deviation, \( s \), of sample data summarized in a frequency distribution table using the formula below. In the formula, \( x \) represents the class midpoint, \( f \) is the class frequency, and \( n \) is the total number of sample values. You are also tasked with comparing the computed standard deviation to the standard deviation obtained from the original list of data values, which is 11.1. **Formula for Calculating Standard Deviation:** \[ s = \sqrt{\frac{n[\sum (f \cdot x^2)] - [\sum (f \cdot x)]^2}{n(n-1)}} \] **Frequency Distribution Table:** | Interval | Frequency | |----------|-----------| | 20-26 | 2 | | 27-33 | 3 | | 34-40 | 9 | | 41-47 | 1 | | 48-54 | 16 | | 55-61 | 36 | | 62-68 | 33 | **Steps:** 1. **Enter the Computed Standard Deviation:** - Round the answer to one decimal place as needed. Enter the result in the text box provided. 2. **Comparison to Given Standard Deviation:** - Consider that a difference of 20% between two values of a standard deviation is deemed significant. - Analyze how the computed value compares with the provided standard deviation of 11.1. **Options for Comparison:** A. The computed value is significantly greater than the given value. B. The computed value is significantly less than the given value. C. The computed value is not significantly different from the given value. **Instructions:** Click to select your answer(s).
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