Find the standard deviation, s, of sample data summarized in the frequency distribution table below by using the formula below, where x represents the class midp frepresents the class frequency, and n represents the total number of sample values. Also, compare the computed standard deviation to the standard deviation obtained from the original list of data values, 11.1 nin - 1) Interval 20-26 27-33 34-40 41-47 48-54 55-61 62-68 Frequency 2 1. 30 38 Standard deviation = Round to one decimal place as needed) Consider a difference of 20% between two values of a standard deviation to be significant. How does this computed value compare with the given standard deviation 11.1? O A. The computed value is significantly greater than the given value O B. The computed value is significantly less than the given value OC. The computed value is not significantly different from the given value

Q: 14. The vectors a and b are such that |a| = 3, |b| = 5 and a. b = -14, then |a – b| = %3D A 62 B V62

A: Solution: Given vectors a and b such that a=3,  b=5 and a·b=-14

Q: ab)c=

A: Given,           abc

Q: V-539 7. V11

A: To Determine:  Simplify

Q: Use the graph to solve the equation: x + 5 = 0.5(x + 3)² - 2 Answer

A:

Q: 9w2=12w+5

A:

Q: k2-35=2k

A:

Q: 4y-12=0

A: 4y = 12 y = 3

Q: 2. K 5x+5 16 35

A:

Q: 4h-3=9

A: We have to find h

Q: 14 +2

A: Adding Fractions Step 1: Make sure the bottom numbers (the denominators) are the same. Step 2: Add…

Q: 24 = 3 + y

A: We have to solve the given expression for y. The expression is 24=3+y.

Q: V = 1 + 3 x5 = V=?

A: The order of operations is a rule that tells the correct sequence of steps for evaluating a math…

Q: -12+(4• 3) (-) I 2-14 - 3)ENTER

A:

Q: Todt 5(-37+4)

A: Given,   ∫  -3t+410dt

Q: 1 +1

A: Given  1+1=

Q: 3p - p

A: Here Given that, 3p-p

Q: 4b2 + 8b +7 = 4

A: Given that

Q: -3w+5=23

A:

Q: 5×-6=37

A: Given,           5×-6=37

Q: 7- + 4 = %3D 8.

A: Given,         738+4

Q: 1 - = AV25 + BV5 + C V25 + V5 + 1 A+ B + C =?

A:

Q: -4d = -64

A: Given  -4d=-64

Q: 8P4 11C7

A:

Q: -5 -2 1

A:

Q: 13-2+3

A: this is a simple calculation question we will simplify this by normal calculation.

Q: w2+7w+12=0

A: w2+7w+12=0 Solve by factoring

Q: a = 2 - 9a

A:

Q: 4т V17 3

A: Modulus function always gives positive quantity in result.

Q: A+12=13

A: Given,   A+12=13     We will solve it for the value of A

Q: Find

A: We know that,                         ∫1xdx=lnx+ c We need to find  ∫4xdx

Q: 2+36=38

A: Given 2+ 36 = 38  Yes the given statement is true .

Q: A3,3=? 2 6 9 3 4 1 7 7 8

A:

Q: 4h aー-5

A: We have to find out

Q: 1. (3, x) 2. (3x + 3, y) 3. (y, cos x) 4. (x + y, x – Y)

A: using online vector field graphing we get 1-A 2-C

Q: z? - 34z + 818 = 0

A:

Q: N+2=4

A: The value is:-

Angles in Circles

Angles within a circle are feasible to create with the help of different properties of the circle such as radii, tangents, and chords. The radius is the distance from the center of the circle to the circumference of the circle. A tangent is a line made perpendicular to the radius through its endpoint placed on the circle as well as the line drawn at right angles to a tangent across the point of contact when the circle passes through the center of the circle. The chord is a line segment with its endpoints on the circle. A secant line or secant is the infinite extension of the chord.

Arcs in Circles

A circular arc is the arc of a circle formed by two distinct points. It is a section or segment of the circumference of a circle. A straight line passing through the center connecting the two distinct ends of the arc is termed a semi-circular arc.