Find the standard deviation, s, of sample data summarized in the frequency distribution table below by using the formula below, where x represents the class midpoint, f represents the class frequency,and n represents the total number of sample values. Also, compare the computed standard deviation to the standard deviation obtained from the original list of data values, 11.1.n(n - 1)Interval20-2627-3334-4041-4748-54Frequency55-61162-688.4173538Standard deviation =(Round to one decimal place as needed.)Consider a difference of 20% between two values of a standard deviation to be significant. How does this computed value compare with the given standard deviation, 11.12O A. The computed value is significantly less than the given value.O B. The computed value is not significantly different from the given value.O C. The computed value is significantly greater than the given value.

For the given data Standard deviation = ? For the statement given select the correct choice

Answered: Find the standard deviation, s, of…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A researcher was conducting a study on the relationship between class size and class performance. He took a random sample of classes offered at the college and noted the the number of students in each class. The frequency distribution below represents the students in each the classes chosen. # of students f 12 21 11 22-31 12 32-41 42 51 28 52 - 61 10 a) What is the sample mean? (round to 2 decimals) b) What is the sample standard deviation? (round to 2 decimals) 23
A group f adult males has foot lengths with a mean of 27.94 cm and a standard deviation of 1.27 cm. Use the range rule of thumb for identifying significant values to identify the limits separating values that are significantly low or significantly high. Is the adult male foot length of 31.0 cm significantly low or significantly high? Explain. Significantly low values are cm or lower. (Type an integer or a decimal. Do not round.) Significantly high values are cm or higher. (Type an integer or a decimal. Do not round.) Select the correct choice below and fill in the answer box(es) o complete your choice. The adult male foot length of 31.0 cm is significantly high because it is greater than cm. OA. (Type an integer or a decimal. Do not round.) OB. The adult male foot length of 31.0 cm is significantly low because it is less than cm. (Type an integer or a decimal. Do not round.) О с. The adult male foot length of 31.0 cm is not significant because it is between cm and (Type integers or…
A teacher used the scores of 9 students to identify the variability of students’ performance on the midterm exam of Statistics and Probability. Scores 16 43 43 41 43 43 44 43 44 What is the average score of the selected students? When arranged from highest to lowest, what is the middle value? What is the range of the data set? What is the sample standard deviation of the data set? (Round off your answer in two decimal places.) What is the sample coefficient of variation of the data set? (Round off your answer in two decimal places. Also, do not put a percent sign.) %
Complete the table to find the sample Mean, Variance and Standard Deviation for the data shown below: {15, 7, 16, 18, 14} (z - 2) (2 - a) 15 16 18 14 Mean Round the following results only at the end to 2 decimal places The Sample Variance s = n – 1 The Sample Standard Deviation s = п - 1
Find the standard deviation for the grouped data. Interval Frequency 50 - 59 60 - 69 9 70-79 11 80 - 89 8 90 99 13.4 11.5 12.8 O 12.2 «Previous Et en ASUS
Find the range and standard deviation. The table below gives the number of hours spent watching TV last week by a sample of 24 children. 10 4 5 10 Range = IQR = 5 1 8 7 8 3 5 9 2 7 3 3 3 7 3 1 8 1 9 2 Standard Deviation = (Please enter an exact answer.) (Please show your answer to 2 decimal places.) (Please show your answer to 1 decimal place.)
Consider the following sample data. Sample A: 13, 23, 33 Sample B: 71, 81, 91 Sample C: 1,050; 1,060; 1,070 (a) Find the mean and standard deviation for each sample. (b) What does this exercise show about the standard deviation? multiple choice The idea is to illustrate that the standard deviation is not a function of the value of the mean. The idea is to illustrate that the standard deviation is a function of the value of the mean.
Find the standard deviation, s, of sample data summarized in the frequency distribution table given below. Also, compare the computed standard deviation to the standard deviation obtained from the original list of data values, 9.0. Interval Frequency 20-26 3 27-33 18 ... 34-40 42 41-47 17 A. The computed value is significantly less than the given value. B. The computed value is not significantly different from the given value. OC. The computed value is significantly greater than the given value. 48-54 7 55-61 1 Standard deviation = (Round to one decimal place as needed.) Consider a difference of 20% between two values of a standard deviation to be significant. How does this computed value compare with the given standard deviation, 9.0?
figure the standard deviation of the distribution of means for a population with a standard deviation of 20 and sample sizes of (a)10, (b)11, (c)100, and (d)101.
Table 2 is showing the frequency distributions of salary for 65 workers in a supermarket. Using coding method, calculate: a) Mean. b) Standard Deviation. Table 2 Salary (RM) Frequency (f) 250.00 – 259.99 8 260.00 – 269.99 10 270.00 – 279.99 16 280.00 - 289.99 14 290.00 – 299.99 10 300.00 – 309.99 310.00 – 319.99
answer 4 5 6 7
A survey was taken in a college class asking how many people lived in each student's household, with the sample data collected as numbers of people and frequencies. The data collected is given in the table below. Number of People (x) Number of Respondents in Survey (f) 1 3 2 6 3 16 4 4 Calculate the standard deviation of the above sample table of frequencies: Round your answer to 2 decimal places and be sure to use the correct formula.

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