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Find the spring force if EI= 2*108 kN.cm² and the Flexibility of the spring P = 0.125 cm/kN. 2 kN/m a EI d k 4m² b EI * k 6m BC TITT K = 800 kN/m Answers in structures lectures: RB = 3.584 kN ETABS Answers: RB = 3.64 kN

Find the spring force if EI= 2*108 kN.cm² and the Flexibility of the spring P = 0.125 cm/kN. 2 kN/m a EI d k 4m² b EI * k 6m BC TITT K = 800 kN/m Answers in structures lectures: RB = 3.584 kN ETABS Answers: RB = 3.64 kN

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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**Transcription for Educational Website:** --- ### Problem Statement **Find the spring force if \( EI = 2 \times 10^8 \, \text{kN} \cdot \text{cm}^2 \) and the flexibility of the spring \( F = 0.125 \, \text{cm/kN} \).** ### Diagram Explanation - The diagram is a structural analysis problem with a beam supported at three points: \( a \), \( b \), and \( c \). - The beam is divided into two segments: - Segment \( ab \): Length of 4 meters. - Segment \( bc \): Length of 6 meters. - There is a uniformly distributed load of \( 2 \, \text{kN/m} \) across segment \( bc \). - The spring is located at point \( b \), characterized by a stiffness \( K = 800 \, \text{kN/m} \). - The beam sections marked as \( EI \) denote their flexural rigidity. ### Calculated Results - **Answers from structures lectures:** \( R_B = 3.584 \, \text{kN} \) - **ETABS Analysis Answer:** \( R_B = 3.64 \, \text{kN} \) ---
Transcribed Image Text:**Transcription for Educational Website:** --- ### Problem Statement **Find the spring force if \( EI = 2 \times 10^8 \, \text{kN} \cdot \text{cm}^2 \) and the flexibility of the spring \( F = 0.125 \, \text{cm/kN} \).** ### Diagram Explanation - The diagram is a structural analysis problem with a beam supported at three points: \( a \), \( b \), and \( c \). - The beam is divided into two segments: - Segment \( ab \): Length of 4 meters. - Segment \( bc \): Length of 6 meters. - There is a uniformly distributed load of \( 2 \, \text{kN/m} \) across segment \( bc \). - The spring is located at point \( b \), characterized by a stiffness \( K = 800 \, \text{kN/m} \). - The beam sections marked as \( EI \) denote their flexural rigidity. ### Calculated Results - **Answers from structures lectures:** \( R_B = 3.584 \, \text{kN} \) - **ETABS Analysis Answer:** \( R_B = 3.64 \, \text{kN} \) ---
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