Find the solution to the recurrence relation an=2nan-1 with the initial condition ao = 3 using an iterative approach by the given following procedure. an=2nan-1 = 2n(2(n-1)an-2) = 2²(n(n-1))an-2 = 22(n(n-1))(2(n − 2)an-3) = 2³(n(n-1)(n − 2))an-3 = ........continuing in the same manner = 2^n(n-1)(n-2)(n-3)....(n-(n-1))an-n = 2^n(n – 1)(n – 2)(n – 3)...1.ao 3.2" n! 2n n! 3.2" (n+1)! O 3.2" (n-1)!

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
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Find the solution to the recurrence relation an = 2nan-1 with the initial condition ao = 3 using an iterative approach by the given following procedure.
an=2nan-1
= 2n(2(n-1)an-2)
2²(n(n-1))an-2
= 2²(n(n-1))(2(n-2) an-3)
= 2³ (n(n-1)(n-2))an-3
= ........continuing in the same manner
=
2^n(n-1)(n-2)(n-3)....(n-(n-1))an-n
= 2^n(n – 1)(n – 2)(n – 3)....1.ao
=
3.2" n!
2n!
3.2" (n+1)!
O 3.2" (n-1)!
Transcribed Image Text:Find the solution to the recurrence relation an = 2nan-1 with the initial condition ao = 3 using an iterative approach by the given following procedure. an=2nan-1 = 2n(2(n-1)an-2) 2²(n(n-1))an-2 = 2²(n(n-1))(2(n-2) an-3) = 2³ (n(n-1)(n-2))an-3 = ........continuing in the same manner = 2^n(n-1)(n-2)(n-3)....(n-(n-1))an-n = 2^n(n – 1)(n – 2)(n – 3)....1.ao = 3.2" n! 2n! 3.2" (n+1)! O 3.2" (n-1)!
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