The possible solution to the recurrence relation T(n)= 2T(n/4) + 1     a θ(n)   b θ(n2)   c θ(nlgn)   d θ(√n)

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The possible solution to the recurrence relation T(n)= 2T(n/4) + 1

 

  a

θ(n)

  b

θ(n2)

  c

θ(nlgn)

  d

θ(√n)

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