Find the solution of the given initial value problem. y(t) = y(t) = y(t) = y(t) == y(t) = y" + 4y= u(t)-3(1), y(0) = 4, y'(0) = 5 - #31(1-cos2r) + 4cos2r + sin2t 5 - #3(1-cos2t) - 4cos2t-sin2t 5 -ul(1+sin2r) + 4sin2r + cos2r u-ul(1-sin2t) + 4cos2r+sin2r -31(1-sin2t) + 4sin2r + cos2r

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A: Given that  y"'+y=e^(-x)+5e^(2x) To find the general solution

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A: Thanks for the question :)And your upvote will be really appreciable ;)

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A: The correct option is b i.e. yp=14sin4x i.e. 14sin4x is the particular solution of the differential…

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Q: 2. Use Method of Undetermined Coefficients: y" - 2y' + 5y = 4e*cos2x + n IN

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A: 2.

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A: Solution of the given question is like as

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A: Note: Since you have asked multiple questions, we will solve the first question for you. If you want…

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A: This question is about ordinary differential equation.

Q: 1. y'=y-xy³e-²x

A: According to guidelines i solve first question only. So kindly request you to repost the remaining…