Prove that the general solution of the differential equation √√1+cos(t) d0=(√1 + cos(t) — t sin(t) 0(t))dt is - -2t√√1+cos(t)+4√√1-cos(t) Se dt + C 0(t) = C 2t√√11 cos(t) 4√1 cos(t)

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A: We will use the formula ddtmn=nm'-mn'n2

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A: The solution is given as

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A: We have not any digital tool .

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A: Solution

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