Find the solution of the given initial-value problem. a) y cos(3x)-sin(3 x) 172 405 b) c) d) O e) O y-cos(3.x) - sin (3x) + 172 405 = cos(3x)+ 172 405 172 405 cos(3x)+sin(3x) + x² cos(3x)+sin(3x)-x²+ 172 405 1)None of the above. - sin(3x) y"+9y=x²+6e [x(0)=1, y'(0)=5] + ²0 = -0
Find the solution of the given initial-value problem. a) y cos(3x)-sin(3 x) 172 405 b) c) d) O e) O y-cos(3.x) - sin (3x) + 172 405 = cos(3x)+ 172 405 172 405 cos(3x)+sin(3x) + x² cos(3x)+sin(3x)-x²+ 172 405 1)None of the above. - sin(3x) y"+9y=x²+6e [x(0)=1, y'(0)=5] + ²0 = -0
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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![Question 3
Find the solution of the given initial-value problem.
a) y = 10 cos(3x) - 2 sin (3x)
172
405
b) y =
c) y =
d) O
e) ○ y=
172
cos(3 x) - sin (3x) -
(3x) + +/- x
cos(3x) + sin (3x)
172
405
172
405
-cos(3x)+sin(3x) +
sin (3x)
y"+9y=x²+6e²
[y(0) = 1, y '(0)=5]
(3 x ) + 1 = 2 x ³² - 3/3/7/2 + 1/²/3
f) None of the above.
172
- cos(3x)+sin(3x) -
(3x) — -— - x² + 3/12 -
405](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff2d77d27-d74c-403f-9e7f-5c95a39ff7d4%2F1bd7efae-bdbe-4c27-b0f1-8975092b22e4%2Fsin0zhe_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Question 3
Find the solution of the given initial-value problem.
a) y = 10 cos(3x) - 2 sin (3x)
172
405
b) y =
c) y =
d) O
e) ○ y=
172
cos(3 x) - sin (3x) -
(3x) + +/- x
cos(3x) + sin (3x)
172
405
172
405
-cos(3x)+sin(3x) +
sin (3x)
y"+9y=x²+6e²
[y(0) = 1, y '(0)=5]
(3 x ) + 1 = 2 x ³² - 3/3/7/2 + 1/²/3
f) None of the above.
172
- cos(3x)+sin(3x) -
(3x) — -— - x² + 3/12 -
405
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