Find the sample size needed to estimate the percentage of residents of one region of a country whoare left-handed. Use a margin of error of one percentage point, and use a confidence level of 95%. Completeparts (a) through (c) below.a. Assume that p and q are unknown.The sample size needed is(Round up to the nearest whole number as needed.)b. Assume that based on prior studies, about 11% of residents of the region are left-handed.The sample size needed is(Round up to the nearest whole number as needed.)*****c. How do the results from parts (a) and (b) change if the entire country is used instead of the one region ofthat country?If the entire country is used instead of the one region of that country, the result from part (a)and the result from part (b)Y

The question is about sample size estimation.Given :Margin of error ( E ) = 0.01Confidence level ( C…

Answered: Find the sample size needed to estimate…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Assume that population mean is to be estimated from the sample described. Use the sample results to approximate the margin of error and 95% confidence interval. n=49, x=55.1 seconds, s=4.8 seconds The margin of error is nothing seconds.
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Solve for B which reads assume prior studies have shown that about 45% of full-time students are in bachelors degree and four years or less. n=
4. At private college the achievement test is used for advanced study placement. Counselors selected a random sample of 144 students from the college and scored their tests by hand before sending them in for computer processing. For this sample, the mean was 450 and s = 29. Construct a 98% confidence interval for the mean.
Find the sample size needed to estimate the percentage of adults who can wiggle their ears. Use a margin of error of 5 percentage points and use a confidence level of 90%. Complete parts (a) and (b) below. a. Assume that p and q are unknown. n = (Round up to the nearest integer.)
Find r for a 0.99 confidence level when the sample size is 4
The following sample data are from a normal population: 10,9,12,14,13,11,6,5 c. With 95% confidence, what is the margin of error for the estimation of the population mean (to 1 decimal)? d. What is the 95% confidence interval for the population mean (to 1 decimal)? d.
According to recent data by the American Marketing Association, 76.5%of people in the 18-24 age group used social media in 2017. You want to find out what the social media proportion is among your classmates who are all between 18 and 24 years old. Suppose you obtain a random sample of 229 students and find that 202 students in this sample are active social media users. Complete parts a through c below. a. Construct a 99% confidence interval to estimate the actual proportion of social media users. A 99% confidence interval to estimate the actual proportion has a lower limit of------ and an upper limit of------- (Round to three decimal places as needed.) b. What is the margin of error for this sample? c. Is there evidence that this proportion matches that of the overall population based on the sample?
I only need part B
Suppose we wish to study the average income of Cactus Club customers, so we plan to conduct a research project with a 95% confidence level. We need our range of error (E) to be no greater than $500. Based on our past experience, we estimate the sample standard deviation to be $5,000. What sample size do you need in order to conduct the research? Select one: a. 372 b. 784 c. 824 d. 385 e. 196
If the analyst decides to increase the sample size (n) from 75 to 100, while maintaining the same confidence level, the width of the confidence interval would then: fluctuate up and down. remain unchanged. decrease. increase.
Construct the indicated confidence interval for the difference in proportions. Assume that the samples are Independent and that they have been randomly selected. A survey of randomly chosen adults found that 45% of the 231 women and 61% of the 275 men follow regular exercise programs. Construct a 95% confidence interval for the difference in the proportions of women and men who have regular exercise programs. O A. (-0.165, -0.155) OB. (0.052, 0.268 ) OC. (-0.246, -0.074) O D. (-0.267, -0.053) O E. (-0.250, -0.070 )

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