18. Find the rejection region for the standardized test statistic for each hypothesis test:1) Ho:u = 27; H1: µ< 27 at the a=0.05 level of significance.2) Ho:H = 52; H,: p#52 at the a=0.05 level of significance.3) Ho:H = 105; H;: µ > 105 at the a=0.01 level of significance.

Answered: Find the rejection region for the…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Test the claim that the mean GPA of night students is larger than the mean GPA of day students at the .01 significance level.The null and alternative hypothesis would be: H0:pN=pDH0:pN=pDH1:pN>pDH1:pN>pD H0:pN=pDH0:pN=pDH1:pN<pDH1:pN<pD H0:μN=μDH0:μN=μDH1:μN>μDH1:μN>μD H0:μN=μDH0:μN=μDH1:μN<μDH1:μN<μD H0:μN=μDH0:μN=μDH1:μN≠μDH1:μN≠μD H0:pN=pDH0:pN=pDH1:pN≠pDH1:pN≠pD The test is: two-tailed right-tailed left-tailed The sample consisted of 25 night students, with a sample mean GPA of 3.43 and a standard deviation of 0.03, and 30 day students, with a sample mean GPA of 3.38 and a standard deviation of 0.02.The test statistic is: ______ (to 2 decimals)The critical value is: ________(to 2 decimals)Based on this we: Fail to reject the null hypothesis Reject the null hypothesis
Test the claim that the proportion of men who own cats is smaller than the proportion of women who own cats at the .05 significance level.The null and alternative hypothesis would be: H0:μM=μFH1:μM<μF H0:pM=pFH1:pM<pF H0:pM=pFH1:pM>pF H0:pM=pFH1:pM≠pF H0:μM=μFH1:μM≠μF H0:μM=μFH1:μM>μF The test is: right-tailed left-tailed two-tailed Based on a sample of 20 men, 40% owned catsBased on a sample of 60 women, 55% owned catsThe test statistic is: (to 2 decimals)The p-value is: (to 2 decimals)Based on this we: Fail to reject the null hypothesis Reject the null hypothesis
Test the claim that the proportion of men who own cats is smaller than the proportion of women who own cats at the .10 significance level.The null and alternative hypothesis would be: H0:pM=pFH0:pM=pFH1:pM>pFH1:pM>pF H0:μM=μFH0:μM=μFH1:μM<μFH1:μM<μF H0:μM=μFH0:μM=μFH1:μM≠μFH1:μM≠μF H0:pM=pFH0:pM=pFH1:pM≠pFH1:pM≠pF H0:μM=μFH0:μM=μFH1:μM>μFH1:μM>μF H0:pM=pFH0:pM=pFH1:pM<pFH1:pM<pF The test is: left-tailed two-tailed right-tailed Based on a sample of 40 men, 35% owned catsBased on a sample of 20 women, 45% owned catsThe test statistic is: (to 2 decimals)The p-value is: (to 2 decimals)Based on this we: Fail to reject the null hypothesis Reject the null hypothesis
Use the technology display, which results from the head injury measurements from car crash dummies listed below. The measurements are in hic (head injury criterion) units, and they are from the same cars used for the table below. Use a 0.01 significance level to test the given claim. Test the null hypothesis that head injury measurements are not affected by an interaction between the type of car (foreign, domestic) and size of the car (small, medium, large). What do you conclude? Click the icon to view the data table and technology display. What are the null and alternative hypotheses? O A. Ho: Head injury measurements are affected by an interaction between type of car and size of the car. H₁: Head injury measurements are not affected by an interaction between type of car and size of the car. O C. Ho: Head injury measurements are not affected by type of car. H₁: Head injury measurements are affected by type of car. xample Get more help. Data table Foreign Domestic Small 294 534 509 411…
Test the claim that the proportion of men who own cats is significantly different than 80% at the 0.01 significance level.The null and alternative hypothesis would be: H0:μ=0.8H0:μ=0.8H1:μ>0.8H1:μ>0.8 H0:μ=0.8H0:μ=0.8H1:μ≠0.8H1:μ≠0.8 H0:p=0.8H0:p=0.8H1:p<0.8H1:p<0.8 H0:μ=0.8H0:μ=0.8H1:μ<0.8H1:μ<0.8 H0:p=0.8H0:p=0.8H1:p>0.8H1:p>0.8 H0:p=0.8H0:p=0.8H1:p≠0.8H1:p≠0.8 The test is: two-tailed left-tailed right-tailed Based on a sample of 35 people, 76% owned catsThe test statistic is: (to 2 decimals)The positive critical value is: (to 2 decimals)Based on this we: Reject the null hypothesis Fail to reject the null hypothesis
Use the technology display, which results from the head injury measurements from car crash dummies listed below. The measurements are in hic (head injury criterion) units, and they are from the same cars used for the table below. Use a 0.01 significance level to test the given claim. Test the null hypothesis that head injury measurements are not affected by an interaction between the type of car (foreign, domestic) and size of the car (small, medium, large). What do you conclude? Click the icon to view the data table and technology display. What are the null and alternative hypotheses? O A. Ho: Head injury measurements are affected by an interaction between type of car and size of B. Ho: Head injury measurements are not affected by an interaction between type of car and size of the car. H₁: Head injury measurements are affected by an interaction between type of car and size of the car. the car. H₁: Head injury measurements are not affected by an interaction between type of car and size…
Test the claim that the proportion of men who own cats is significantly different than the proportion of women who own cats at the 0.2 significance level.The null and alternative hypothesis would be: H0:pM=pFH0:pM=pFH1:pM<pFH1:pM<pF H0:μM=μFH0:μM=μFH1:μM≠μFH1:μM≠μF H0:pM=pFH0:pM=pFH1:pM≠pFH1:pM≠pF H0:pM=pFH0:pM=pFH1:pM>pFH1:pM>pF H0:μM=μFH0:μM=μFH1:μM>μFH1:μM>μF H0:μM=μFH0:μM=μFH1:μM<μFH1:μM<μF The test is: two-tailed right-tailed left-tailed Based on a sample of 60 men, 30% owned catsBased on a sample of 40 women, 40% owned catsThe test statistic is: (to 2 decimals)The p-value is: (to 2 decimals)Based on this we: Reject the null hypothesis Fail to reject the null hypothesis Check AnswerQuestion 14
Use the technology display, which results from the head injury measurements from car crash dummies listed below. The measurements are in hic (head injury criterion) units, and they are from the same cars used for the table below. Use a 0.10 significance level to test the given claim. Test the null hypothesis that head injury measurements are not affected by an interaction between the type of car (foreign, domestic) and size of the car (small, medium, large). What do you conclude? A. F = 1.41, p-value = 0.281 B. F = 2.25, p-value = 0.159 C. F = 1.37, p-value = 0.290 D. F = 0.44, p-value = 0.655
Test the claim that the proportion of men who own cats is significantly different than the proportion of women who own cats at the 0.1 significance level. The null and alternative hypothesis would be: H0:μM=μFH0:μM=μFH1:μM>μFH1:μM>μF H0:pM=pFH0:pM=pFH1:pM>pFH1:pM>pF H0:pM=pFH0:pM=pFH1:pM≠pFH1:pM≠pF H0:μM=μFH0:μM=μFH1:μM<μFH1:μM<μF H0:μM=μFH0:μM=μFH1:μM≠μFH1:μM≠μF H0:pM=pFH0:pM=pFH1:pM<pFH1:pM<pF The test is: right-tailed left-tailed two-tailed Based on a sample of 40 men, 45% owned catsBased on a sample of 40 women, 70% owned cats The test statistic is: (to 2 decimals) The positive critical value is: (to 2 decimals) Based on this we: Reject the null hypothesis Fail to reject the null hypothesis
Test the claim that the proportion of people who own cats is smaller than 60% at the 0.005 significance level.The null and alternative hypothesis would be: H0:μ=0.6H0:μ=0.6H1:μ≠0.6H1:μ≠0.6 H0:p=0.6H0:p=0.6H1:p≠0.6H1:p≠0.6 H0:p≤0.6H0:p≤0.6H1:p>0.6H1:p>0.6 H0:μ≥0.6H0:μ≥0.6H1:μ<0.6H1:μ<0.6 H0:p≥0.6H0:p≥0.6H1:p<0.6H1:p<0.6 H0:μ≤0.6H0:μ≤0.6H1:μ>0.6H1:μ>0.6 The test is: two-tailed right-tailed left-tailed Based on a sample of 200 people, 51% owned catsThe test statistic is: (to 2 decimals)The p-value is: (to 2 decimals)Based on this we: Reject the null hypothesis Fail to reject the null hypothesis
Test the claim that the proportion of people who own cats is significantly different than 80% at the 0.2 significance level. The null and alternative hypothesis would be: Ho: p= 0.8 Ho: ≤ 0.8 Hop: 0.8 Ho:p> 0.8 Ho: 0.8 Ho:p 0.8 H₁:µ 0.8 H₁:p 0.8 The test is: right-tailed two-tailed left-tailed = Based on a sample of 300 people, 82% owned cats The p-value is: (to 2 decimals)
Test the claim that the proportion of men who own cats is significantly different than the proportion of women who own cats at the 0.2 significance level.The null and alternative hypothesis would be: H0:μM=μFH0:μM=μFH1:μM<μFH1:μM<μF H0:pM=pFH0:pM=pFH1:pM<pFH1:pM<pF H0:pM=pFH0:pM=pFH1:pM≠pFH1:pM≠pF H0:pM=pFH0:pM=pFH1:pM>pFH1:pM>pF H0:μM=μFH0:μM=μFH1:μM>μFH1:μM>μF H0:μM=μFH0:μM=μFH1:μM≠μFH1:μM≠μF The test is: right-tailed left-tailed two-tailed Based on a sample of 40 men, 25% owned catsBased on a sample of 20 women, 30% owned catsThe test statistic is: (to 2 decimals)The p-value is: (to 2 decimals)Based on this we: Reject the null hypothesis Fail to reject the null hypothesis

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Find the rejection region for the standardized test statistic for each hypothesis test: 1) Ho:u = 27; H1: µ< 27 at the a=0.05 level of significance. 2) Ho:u = 52; H1: p#52 at the a=0.05 level of significance. %3D 3) Ho:H = 105; H;: µ > 105 at the a=0.01 level of significance. %3D