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Find the real number solutions for (x+3)(4x²+41) = (x+3)(3x² + 5) using Factoring By Grouping Show every step

Find the real number solutions for (x+3)(4x²+41) = (x+3)(3x² + 5) using Factoring By Grouping Show every step

Algebra and Trigonometry (6th Edition)
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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Find the real solutions for (x + 6)(2x² - 9) = (x + 6)(x² +40) (x+6) (2x²9)(x+6) (x²40) Tern 2 153 Scot Term 1 (X+6) ((2x²29) - (x²+40) ) = 0 (x + 6 x 2x² 4 - x² - 40 ) = 0 (X+6)/(x²-49)=0 everyone meet Big Math X+6=0 X=-6 x² 49=0 +49449 x².49- √√x² = +√49 X=+7 {-6, -7}
Transcribed Image Text:Find the real solutions for (x + 6)(2x² - 9) = (x + 6)(x² +40) (x+6) (2x²9)(x+6) (x²40) Tern 2 153 Scot Term 1 (X+6) ((2x²29) - (x²+40) ) = 0 (x + 6 x 2x² 4 - x² - 40 ) = 0 (X+6)/(x²-49)=0 everyone meet Big Math X+6=0 X=-6 x² 49=0 +49449 x².49- √√x² = +√49 X=+7 {-6, -7}
Find the real number solutions for (x+3)(4x²+41) = (x+3)(3x² + 5) using Factoring By Grouping. Show every step
Transcribed Image Text:Find the real number solutions for (x+3)(4x²+41) = (x+3)(3x² + 5) using Factoring By Grouping. Show every step
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