2x+14, 5x+5 8x - 4

Q: If JKLM is a rectangle, JL = 2x + 5, and MK = 7x – 40 %3D - .K N.

A: For solving the linear expression separate the constant term and x's term on each side of = sign.

Q: 4) Which setup should be used to solve for y? * 57° 15 Cos 57 = %3D sin 57 = %3D 15 15

A:

Q: 15 53

A: We have to find the value of x  Given ,  A right triangle and Hypotenuse = 15  Perpendicular = x  θ…

Q: х + 29 3x + 9 2x

A: Given:  Figure is of quadrilateral, where interior angles are given in terms of x. Angles are given…

Q: 14. Area of the rectangle = 22 2x + 1 3x+1

A:

Q: 10. (7x + 9) K N 46

A:

Q: 122 100° to 144 4.

A: From the interior angles sum of polygon

Q: the value of x.

A:

Q: Find the value of x. 137° to 25 155°

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Q: (62- 5x) W • 133° V. U

A: Find the value of x

Q: 7. Find the value of x. (7x + 23) (21x-11)

A: Find x

Q: 3. 78 + x = 3 ( mod 5) 4. 89 = (x + 3) ( mod 4)

A:

Q: (17x-20) 59 75

A:

Q: Find the value of x

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Q: D. 87 (5x + 2) C 39*

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Q: 1. 1 + 1 = 1 y 2. x2 + y? = 25 %3D

A: Answer (1): The given equation is: 1x+1y=1 To solve this equation for y in terms of x, subtract 1x…

Q: Find the value of x.

A: we have to find the value for x in the given triangle

Q: Find the value of x. 9 12 14 The value of x is

A: Use the ratio proportion and simplify for x.

Q: (21x – 10)° 19x°

A: given that∠ABP=(21x-10)°∠BCQ=19x°We have to find the value of x

Q: Use the given figure to find the following values

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Q: 18 37° 2x + 4 37° Q

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Q: Find the value of x. (3x 14) (2x + 10)°

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Q: 14. If a || b, solve for x for y. (13r-27) (9y + 19) (10r+ 6)

A: x = 11o & y = 5o

Q: 2) Solve for x and y. 45° 13V2

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Q: Find the value of x. 43

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Q: Step 1: 8(8x) = 9(15) Step 2: 16x = 135 6, Step 3: divide both sides by 16. 15 Step 4: x = 8.44

A: mistake in applying theorum

Q: Solve for the values of x. H. 27° 130° of Q.

A: Given: ∠HOT=130° and ∠HPT=27°

Q: The next three questions concern the following situation. Consider the lines r(t) = t+ and q(s) =…

A:

Q: Find the value of x. 5 18

A: We use Trigonometry ratios cos(x) = (Base)/(Hypotenuse)