Find the rate law and the individual and overall reaction orders for the reaction H2 + 12 ---> 2HI using the following data at 450 degrees Celsius. * Experiment Initial Rate (mol/L·s) Initial [H,] (mol/L) Initial [1,] (mol/L) 1.9X10-23 1.1X10-22 9.3X10-23 1.9X10-22 1 0.0113 0.0011 2 0.0220 0.0033 3 0.0550 0.0011 4 0.0220 0.0056 Rate = k[H2]*m[12]*n. From Expts 1 and 3, m = 1. From Expts 2 and 4, n = 1. Therefore, the rate is k[H2][12]; second order overall. Rate = k[H2]*m[12]^n. From Expts 1 and 3, m = 1. From Expts 2 and 4, n = 2. Therefore, the rate is k[H2][12]^2; third order overall. Rate = k[H2]*m[12]^n. From Expts 1 and 3, m = 1. From Expts 2 and 4, n = 0. Therefore, the rate is k[H2]; first order overall. O The reaction does not occur.
Find the rate law and the individual and overall reaction orders for the reaction H2 + 12 ---> 2HI using the following data at 450 degrees Celsius. * Experiment Initial Rate (mol/L·s) Initial [H,] (mol/L) Initial [1,] (mol/L) 1.9X10-23 1.1X10-22 9.3X10-23 1.9X10-22 1 0.0113 0.0011 2 0.0220 0.0033 3 0.0550 0.0011 4 0.0220 0.0056 Rate = k[H2]*m[12]*n. From Expts 1 and 3, m = 1. From Expts 2 and 4, n = 1. Therefore, the rate is k[H2][12]; second order overall. Rate = k[H2]*m[12]^n. From Expts 1 and 3, m = 1. From Expts 2 and 4, n = 2. Therefore, the rate is k[H2][12]^2; third order overall. Rate = k[H2]*m[12]^n. From Expts 1 and 3, m = 1. From Expts 2 and 4, n = 0. Therefore, the rate is k[H2]; first order overall. O The reaction does not occur.
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![Find the rate law and the individual and overall reaction orders for the reaction
H2 + 12 ---> 2HI using the following data at 450 degrees Celsius. *
Experiment Initial Rate (mol/L·s) Initial [H,] (mol/L)
Initial [l,] (mol/L)
1.9X10-23
1.1X10-22
9.3X10-23
1.9X10-22
1
0.0113
0.0011
2
0.0220
0.0033
3
0.0550
0.0011
4
0.0220
0.0056
Rate = k[H2]*m[12]*n. From Expts 1 and 3, m = 1. From Expts 2 and 4, n = 1. Therefore,
the rate is k[H2][12]; second order overall.
Rate = k[H2]*m[12]^n. From Expts 1 and 3, m = 1. From Expts 2 and 4, n = 2. Therefore,
the rate is k[H2][12]^2; third order overall.
Rate = k[H2]*m[12]^n. From Expts 1 and 3, m = 1. From Expts 2 and 4, n = 0. Therefore,
the rate is k[H2]; first order overall.
O The reaction does not occur.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F842c2761-c823-47a3-9b73-661fe27147d3%2Fab98ee9b-a751-4cf0-846a-2552a3de7a3a%2Fslb4t4g_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Find the rate law and the individual and overall reaction orders for the reaction
H2 + 12 ---> 2HI using the following data at 450 degrees Celsius. *
Experiment Initial Rate (mol/L·s) Initial [H,] (mol/L)
Initial [l,] (mol/L)
1.9X10-23
1.1X10-22
9.3X10-23
1.9X10-22
1
0.0113
0.0011
2
0.0220
0.0033
3
0.0550
0.0011
4
0.0220
0.0056
Rate = k[H2]*m[12]*n. From Expts 1 and 3, m = 1. From Expts 2 and 4, n = 1. Therefore,
the rate is k[H2][12]; second order overall.
Rate = k[H2]*m[12]^n. From Expts 1 and 3, m = 1. From Expts 2 and 4, n = 2. Therefore,
the rate is k[H2][12]^2; third order overall.
Rate = k[H2]*m[12]^n. From Expts 1 and 3, m = 1. From Expts 2 and 4, n = 0. Therefore,
the rate is k[H2]; first order overall.
O The reaction does not occur.
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