Find the points at which the graph of the equation has a vertical or horizontal tangent line. 25x2 + y² 50x+10y + 25 = 0 horizontal tangents (x, y) = 1, -15 (x, y) = (1,5 vertical tangents v) = -1.-5 (smaller y-value) (larger y-value) (smaller x-value)
Find the points at which the graph of the equation has a vertical or horizontal tangent line. 25x2 + y² 50x+10y + 25 = 0 horizontal tangents (x, y) = 1, -15 (x, y) = (1,5 vertical tangents v) = -1.-5 (smaller y-value) (larger y-value) (smaller x-value)
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Transcribed Image Text:Find the points at which the graph of the equation has a vertical or horizontal tangent line.
25x2 + y2
50x+10y + 25 = 0
(x, y) = (1, -15
(x, y) = (1,5
(x, y) = (-1,- 5
(x, y) =(3, -5
horizontal tangents
vertical tangents
(smaller y-value)
(larger y-value)
(smaller x-value)
(larger x-value)
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