Find the p-value based on a standard normal distribution for each of the following standardized test statistics. (a) z = -1.10 for a left tail test for a mean Round your answer to three decimal places. p-value = i eTextbook and Media (b) z = 4.08 for a right tail test for a proportion Round your answer to three decimal places. p-value = i eTextbook and Media (c) z = -1.49 for a two-tailed test for a difference in means Round your answer to three decimal places. p-value = i eTextbook and Media

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