A survey conducted on a group of patients showed that these patients either have a heart disease only of a lung disease only or both diseases. It was noted that: • 60 % of the patients are men. • Among the men: 20 % have a heart disease only and 50% have a lung disease only. Among the women: 25% have a heart disease only and 40% have both diseases. One patient is selected at random. Consider the following events: • M: "The selected patient is a men"; • H: "The selected patient has a heart disease only" • L: "The selected patient has a lung disease only"; • B: "The selected patient has both diseases".
Inverse Normal Distribution
The method used for finding the corresponding z-critical value in a normal distribution using the known probability is said to be an inverse normal distribution. The inverse normal distribution is a continuous probability distribution with a family of two parameters.
Mean, Median, Mode
It is a descriptive summary of a data set. It can be defined by using some of the measures. The central tendencies do not provide information regarding individual data from the dataset. However, they give a summary of the data set. The central tendency or measure of central tendency is a central or typical value for a probability distribution.
Z-Scores
A z-score is a unit of measurement used in statistics to describe the position of a raw score in terms of its distance from the mean, measured with reference to standard deviation from the mean. Z-scores are useful in statistics because they allow comparison between two scores that belong to different normal distributions.
Pleaze solve asap if possible my exam is tomorrow and i need to understand this question. And it is not graded this is a sample exam the teacher gave us. Thank you!
![A survey conducted on a group of patients showed that these patients either have a heart disease only or a
lung disease only or both diseases. It was noted that:
• 60 % of the patients are men.
• Among the men: 20 % have a heart disease only and 50% have a lung disease only.
• Among the women: 25% have a heart disease only and 40% have both diseases.
One patient is selected at random.
Consider the following events:
• M: "The selected patient is a men";
• H: "The selected patient has a heart disease only"
• L: "The selected patient has a lung disease only";
• B: "The selected patient has both diseases".
Part A
1) Calculate the probabilities P(MnH),P(MOL) and P(MoB).
2) Calculate P(H), P(L) and verify that P(B) =0.34.
33
3) Show that P(HUL)=-
50
4) Knowing that the selected patient has only one disease, calculate the probability that this patient has
a heart disease.
Part B
The group consists of 500 patients. The names of three patients were randomly and simultaneously
selected to win an insurance policy each.
Knowing that the three selected patients have both diseases, calculate the probability that they are men.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F22557bfc-bb49-4038-ad3f-c9fb5d702800%2F1ad43e31-e2cd-492f-a4ac-5e6bfab88569%2F3fvku35_processed.jpeg&w=3840&q=75)
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