**Educational Content: Torque Calculation****Problem Statement:**Find the net torque on the wheel in the figure below about the axle through point O, which is perpendicular to the page. Use the measurements \( a = 11.0 \, \text{cm} \) and \( b = 25.0 \, \text{cm} \).*(Indicate the direction with the sign of your answer. Assume that the positive direction is counterclockwise.)***Net Torque:**-3.43 N·m**Diagram Explanation:**The diagram illustrates a wheel with several forces applied to it:1. **Forces Applied:** - A force of 10.0 N is applied horizontally to the right at the edge of the outer circle. - A force of 9.0 N is applied vertically downward at the edge of the outer circle. - A force of 12.0 N is applied at an angle of 30.0° below the horizontal to the left at the edge of the inner circle with radius \( a \).2. **Circle Structure:** - The inner circle with center O has a radius \( a = 11.0 \, \text{cm} \). - The outer circle with center O has a radius \( b = 25.0 \, \text{cm} \).**Calculation Insight:**The torque (\(\tau\)) is calculated using the formula:\[ \tau = r \cdot F \cdot \sin(\theta) \]where \( r \) is the radius, \( F \) is the force, and \(\theta\) is the angle between the force vector and the lever arm. The net torque is the sum of individual torques applied to the wheel, each considered with their respective direction (counterclockwise as positive and clockwise as negative).

Answered: Image /qna-images/answer/24e2074c-a6a6-41a5-8bfb-465ce3d2195a.jpg

Find the net torque on the wheel in the figure below about the axle through O perpendicular to the page, taking a = 11.0 cm and b = 25.0 cm. (Indicate the direction with the sign of your answer. Assume that the positive direction is counterclockwise.) -3.43 N.m 12.0 N 30.0% sa b 10.0 N 9.00 N Q

Find the net torque on the wheel in the figure below about the axle through O perpendicular to the page, taking a = 11.0 cm and b = 25.0 cm. (Indicate the direction with the sign of your answer. Assume that the positive direction is counterclockwise.) -3.43 N.m 12.0 N 30.0% sa b 10.0 N 9.00 N Q

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Concept explainers

Torque

Torque is the rotational equivalent of linear force in physics and mechanics. Based on the course of study, it is also known as the moment of force, rotational force, or turning effect.

Question

**Educational Content: Torque Calculation**

**Problem Statement:**

Find the net torque on the wheel in the figure below about the axle through point O, which is perpendicular to the page. Use the measurements \( a = 11.0 \, \text{cm} \) and \( b = 25.0 \, \text{cm} \).

*(Indicate the direction with the sign of your answer. Assume that the positive direction is counterclockwise.)*

**Net Torque:**

-3.43 N·m

**Diagram Explanation:**

The diagram illustrates a wheel with several forces applied to it:

1. **Forces Applied:**
- A force of 10.0 N is applied horizontally to the right at the edge of the outer circle.
- A force of 9.0 N is applied vertically downward at the edge of the outer circle.
- A force of 12.0 N is applied at an angle of 30.0° below the horizontal to the left at the edge of the inner circle with radius \( a \).

2. **Circle Structure:**
- The inner circle with center O has a radius \( a = 11.0 \, \text{cm} \).
- The outer circle with center O has a radius \( b = 25.0 \, \text{cm} \).

**Calculation Insight:**

The torque (\(\tau\)) is calculated using the formula:

\[ \tau = r \cdot F \cdot \sin(\theta) \]

where \( r \) is the radius, \( F \) is the force, and \(\theta\) is the angle between the force vector and the lever arm. The net torque is the sum of individual torques applied to the wheel, each considered with their respective direction (counterclockwise as positive and clockwise as negative).

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