Find the net torque on the wheel in the figure below about the axle through O perpendicular to the page, taking a = 12.0 cm and b = 30.0 cm. 10.0 N 12.0 N 30.0 = b 9.00 N Step 1 The total torque on an object is the sum of the individual torques. Remember that d is the perpendicular distance from the rotation axis to the line of action of the force F, called the moment arm or lever arm of F. We have the following. Σr = Σ Fd N)(0.12 m) - (10.0 N)([ m)-([ N-m This represents a torque vector that points into the plane of the page, and results in a ---Select--- N)(0.3 m) ✓turning by the force.

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Find the net torque on the wheel in the figure below about the axle through O perpendicular to the page, taking a = 12.0 cm and b = 30.0 cm.
10.0 N
12.0 N
30.0
=
b
Step 1
The total torque on an object is the sum of the individual torques. Remember that d is the perpendicular distance from the rotation axis to the line of action of the
force F, called the moment arm or lever arm of F. We have the following.
Στ = Στα
9.00 N
IN)(0.12 m) -(10.0 N)(
N.m
m) - (
This represents a torque vector that points into the plane of the page, and results in a ---Select---
N) (0.3 m)
turning by the force.
Transcribed Image Text:Find the net torque on the wheel in the figure below about the axle through O perpendicular to the page, taking a = 12.0 cm and b = 30.0 cm. 10.0 N 12.0 N 30.0 = b Step 1 The total torque on an object is the sum of the individual torques. Remember that d is the perpendicular distance from the rotation axis to the line of action of the force F, called the moment arm or lever arm of F. We have the following. Στ = Στα 9.00 N IN)(0.12 m) -(10.0 N)( N.m m) - ( This represents a torque vector that points into the plane of the page, and results in a ---Select--- N) (0.3 m) turning by the force.
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