120 0.035 1 + 12 -1 (190000 269485.527 - 143.4325x If 1 find the monthly payment that will pay off a loan of $190,000 in 10 years at the interest rate of 3.5%.

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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The problem involves finding the monthly payment for a loan using a matrix equation. The matrix equation is given as follows:

\[
\begin{bmatrix}
\left(1 + \frac{0.035}{12}\right) & -1 \\
0 & 1
\end{bmatrix}^{120}
\begin{bmatrix}
190000 \\
x
\end{bmatrix}
=
\begin{bmatrix}
269485.527 - 143.4325x \\
x
\end{bmatrix}
\]

The task is to find the monthly payment that will pay off a loan of $190,000 in 10 years at an interest rate of 3.5%.

**Explanation:**

- The matrix on the left includes calculations for the monthly interest rate \(\frac{0.035}{12}\).
- The matrix exponentiation, denoted by \(^{120}\), refers to the 120 monthly payments over 10 years.
- The vector \(\begin{bmatrix} 190000 \\ x \end{bmatrix}\) represents the loan amount of $190,000 and the unknown monthly payment \(x\).
- The resulting vector \(\begin{bmatrix} 269485.527 - 143.4325x \\ x \end{bmatrix}\) represents the remaining balance and monthly payments after the loan term.

The problem asks you to solve for \(x\), the monthly payment amount.
Transcribed Image Text:The problem involves finding the monthly payment for a loan using a matrix equation. The matrix equation is given as follows: \[ \begin{bmatrix} \left(1 + \frac{0.035}{12}\right) & -1 \\ 0 & 1 \end{bmatrix}^{120} \begin{bmatrix} 190000 \\ x \end{bmatrix} = \begin{bmatrix} 269485.527 - 143.4325x \\ x \end{bmatrix} \] The task is to find the monthly payment that will pay off a loan of $190,000 in 10 years at an interest rate of 3.5%. **Explanation:** - The matrix on the left includes calculations for the monthly interest rate \(\frac{0.035}{12}\). - The matrix exponentiation, denoted by \(^{120}\), refers to the 120 monthly payments over 10 years. - The vector \(\begin{bmatrix} 190000 \\ x \end{bmatrix}\) represents the loan amount of $190,000 and the unknown monthly payment \(x\). - The resulting vector \(\begin{bmatrix} 269485.527 - 143.4325x \\ x \end{bmatrix}\) represents the remaining balance and monthly payments after the loan term. The problem asks you to solve for \(x\), the monthly payment amount.
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